Answer:
The child will take 5.952 seconds to travel from the top of the hill to the bottom.
Explanation:
Given that the child accelerates uniformly and that both initial (
) and final speeds (
), measured in meters per second, and acceleration (
), measured in meters per square second, are known, we proceed to use the following kinematic equation to determine the time taken to travel from the top of the hill to the bottom (
), measured in seconds, is:
(1)
If we know that
,
and
, then the time taken is:

The child will take 5.952 seconds to travel from the top of the hill to the bottom.
Answer:
Add an arrow above the symbol p to show it is a vector. Sometimes it is italicized in textbooks.
Explanation:
<h3>The metre is the length of the path travelled by light in vacuum during a time interval of 1299 792 458 of a second.</h3>
Answer:
option (a)
Explanation:
the angular velocity of the carousel is same througout the motion, so the angular velocity of all the horses is same, but the linear velocity is different for different horses.
As the angular displacement of all the horses are same in the same time so the angular velocity is same.
The relation between the linear velocity and the angular velocity is given by
v = r ω
where, v is linear velocity and r be the distance between the horse and axis of rotation and ω be the angular velocity.
So, the angular velocity of Alice horse is same as the angular velocity of Bob horse.
ωA = ωB
Thus, option (a) is true.
Answer:
The escape speed for the craft is 1.49 m/s.
Explanation:
In this case we need to find the escape speed for a craft launched from a space elevator at a height of 56,000 km. The escape velocity is given by :

Here,
G is universal gravitational constant
M is mass of earth
d = r + h, r is radius of Earth

So, the escape speed for the craft is 1.49 m/s.