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kobusy [5.1K]
2 years ago
5

A multidimensional database (MDDB) is a type of database in which data can be viewed from multiple dimensions; commonly used wit

h ____.
Physics
1 answer:
xeze [42]2 years ago
7 0

A multidimensional database (MDDB) is a type of database in which data can be viewed from multiple dimensions; commonly used with <u>MOLAP</u>.

A multidimensional database affords the ability to swiftly procedure statistics and generates solutions quickly. MDBs let users ask questions about corporations' operations and traits.

The multidimensional databases make use of MOLAP (multidimensional online analytical processing) to get admission to its statistics. They permit the users to fast get answers to their requests by means of generating and analyzing the records as a substitute quickly. The information in multidimensional databases is stored in a records dice format.

In a  dimensional database, you have rows and columns, represented by means of X and Y. In a multidimensional database, you have got X, Y, Z, etc. depending on the number of dimensions in your statistics. Beneath is an instance of a 3-Dimensional statistics Array represented in a relational table and in 3-D.

Learn more about the multidimensional databases here: brainly.com/question/518894

#SPJ1

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If X = 5 and Y = 3, what does Z equal? <br> 2X + 2Z = 10Y
Margarita [4]
2(5) + 2 (z) = 10{3}
10 + 2z= 30
2z=20
z=10
4 0
4 years ago
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Adjacent antinodes of a standing wave on a string are 15.0 cm apart. A particle at an antinode oscillates in simple harmonic mot
timama [110]

Answer:

Explanation:

A ) Distance between two adjacent  anti-node will be equal to distance between two adjacent  nodes . So the required distance is 15 cm .

B )  wave-length, amplitude, and speed of the two traveling waves that form this pattern are as follows

wave length = same as wave length of wave pattern formed. so it is 30 cm

amplitude = 1/2 the amplitude of wave pattern formed so it is .850 / 2 = .425 cm

Speed =   frequency x wavelength ( frequency = 1 / time period )

= 1 / .075) x 30 cm

400 cm / m

C ) maximum speed

= ω A

= (2π / T) x A

= 2 X 3.14 x .85 / .075 cm / s

= 71.17 cm / s

minimum speed is zero.

D ) The shortest distance along the string between a node and an antinode

= Wavelength / 4

= 30 / 4

= 7.5 cm

3 0
3 years ago
At what location in a circuit is the electrical potential energy the greatest
Eduardwww [97]

It's not the potential energy.  It's just the potential.

It's greatest at the positive terminal of the battery or power supply.


4 0
3 years ago
What should the Architect do to ensure Field-Level Security is enforced on a custom Visualforce page using the Standard Lead Con
OLEGan [10]

Answer:

the Architect should use {!$FieldType.lead.accessible} expression within the Visualforce page.

Explanation:

Visualforce is a framework that allows developers to build complex,  user friendly interfaces that can be hosted primarily on the Lightning Platform

Controllers provide access to the data that should be displayed in a page, and can modify component behavior. a number of standard controllers are provided by The Lightning platform that contain  functionality and logic that which are used for standard Salesforce pages

The Architect should Use the expression {!$FieldType.lead.accessible}  within the Visualforce page.

3 0
4 years ago
A small truck has a mass of 2145 kg. How much work is required to decrease the speed of the vehicle from 25.0 m/s to 12.0 m/s on
MAXImum [283]

Answer:

The work required is -515,872.5 J

Explanation:

Work is defined in physics as the force that is applied to a body to move it from one point to another.

The total work W done on an object to move from one position A to another B is equal to the change in the kinetic energy of the object. That is, work is also defined as the change in the kinetic energy of an object.

Kinetic energy (Ec) depends on the mass and speed of the body. This energy is calculated by the expression:

Ec=\frac{1}{2} *m*v^{2}

where kinetic energy is measured in Joules (J), mass in kilograms (kg), and velocity in meters per second (m/s).

The work (W) of this force is equal to the difference between the final value and the initial value of the kinetic energy of the particle:

W=\frac{1}{2} *m*v2^{2}-\frac{1}{2} *m*v1^{2}

W=\frac{1}{2} *m*(v2^{2}-v1^{2})

In this case:

  • W=?
  • m= 2,145 kg
  • v2= 12 \frac{m}{s}
  • v1= 25 \frac{m}{s}

Replacing:

W=\frac{1}{2} *2145 kg*((12\frac{m}{s} )^{2}-(25\frac{m}{s} )^{2})

W= -515,872.5 J

<u><em>The work required is -515,872.5 J</em></u>

3 0
3 years ago
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