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Nesterboy [21]
3 years ago
15

Identify the relationship between the two quantities in the given question as causation or

Physics
1 answer:
Mumz [18]3 years ago
4 0

Answer:2. The number of miles driven and the amount of gas used.

Explanation:

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A 0.40-kg mass, attached to the end of a 0.75-m string, is whirled around in a circular horizontal path. If the maximum tension
hichkok12 [17]

To solve this problem we will apply the concepts given from the circular movement of the bodies for which we have that the centripetal Force is defined as a product between the mass and the velocity squared at the rate of rotation, mathematically this is

F_c = \frac{mv^2}{r}

Where,

m = Mass

v = Velocity

r = Radius

Our values are given as

m = 0.4kg\\r = 0.75m\\F_c = 450N

Rearranging to find the velocity we have that,

F_c = \frac{mv^2}{r}

v = \sqrt{\frac{F_c * r}{m}}

v = \sqrt{\frac{450 * 0.75}{0.4}}

v = 29.0474m/s

Therefore the  maximum speed can the mass have if the string is not to break is 29m/s

3 0
3 years ago
Please help! asap! brainliest to the right answer!
JulijaS [17]
It is gonna be C 0.37 and 19.1
4 0
3 years ago
Read 2 more answers
Calculate the energy (in eV/atom) for vacancy formation in some metal, M, given that the equilibrium number of vacancies at 296o
Schach [20]

Explanation:

The given data is as follows.

       Temperature of metal = 296^{o}C = (296 + 273) K

                                            = 569 K

     Density of the metal = 8.85 g/cm^{3} = 8.85 \times 10^{-6} g/m^{3}      (as 1 cm^{3} = 10^{-6} m^{3})

     Atomic mass = 51.40 g/mol

    Vacancies = 9.19 \times 10^{23} m^{-3}

Formula to calculate the number of atomic sites is as follows.

           n = \frac{\rho \times N_{A}}{\text{atomic weight}}

              = \frac{8.85 \times 10^{-6} \times 6.022 \times 10^{23}}{51.40 g/mol}

              = 1.036 \times 10^{17} atom/m^{3}

Now, we will calculate the energy as follows.

                E = -KT \times ln (\frac{\text{no. of vacancies}}{\text{no. of atomic sites}})

where,    K = 8.62 \times 10^{-5}

         E = -8.62 \times 10^{-5} \times 569 K \times ln (\frac{9.19 \times 10^{23}}{1.036 \times 10^{17} atom/m^{3}})

               = 78.46 eV/atom

Therefore, we can conclude that energy (in eV/atom) for vacancy formation in given metal, M, is 78.46 eV/atom.

6 0
4 years ago
Please help on this one?
valina [46]

I believe that it is d correct me if wrong because the higher the temperature the more active the molecules are gonna be, but the graph does not explicitly state that, so you can say the answer is d (if not the answer is c) (sorry if wrong)

3 0
3 years ago
The solid steel shaft AC has a diameter of 25 mm and is supported by smooth bearings at D and E. It is coupled to a motor at C ,
Degger [83]

Answer:

Maximum shear stress in region AB=1.04 MPa

Maximum shear stress in region BC=3.11 MPa

Explanation:

The explanation is attached in the attachments.

4 0
4 years ago
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