Distance is the total length of an object's path. Displacement is the overall change in position, ie. how far an object is from its initial position.
The court is 30 m long, so a path going back and forth once is 60 m long. Going along this path 6 times totals 360 m.
The end point is the same as the starting point, so the displacement is 0 m.
Answer:
D. All of the above.
Explanation:
Iron has a constant density, which means 2-kg block will have twice as much volume as 1-kg block; therefore, choice A is correct.
Inertia is defined by the equation F = ma: it measures how hard it is to change the motion of an object. The inertia of the the 1-kg solid iron is
F = 1a,
And the inertia of the 2-kg solid iron is
F = 2a,
which is twice as much that of the 1-kg block; therefore, choice B is correct.
The mass of the 2-kg block is twice as much as that of the 1-kg block; therefore, choice C is also correct.
Thus, all of the choices are correct (D).
Speed with which initially car is moving is 21 m/s
Reaction time = 0.50 s
distance traveled in the reaction time d = v t
d = 21 * 0.50 = 10.5 m
deceleration after this time = -10 m/s^2
now the distance traveled by the car after applying bakes
so total distance moved before it stop
d = 22.05 + 10.5 = 32.55 m
so the distance from deer is 35 - 32.55 = 2.45 m
now to find the maximum speed with we can move we will assume that we will just touch the deer when we stop
so our distance after brakes are applied is d = 35 - 10.5 = 24.5 m
again by kinematics
so maximum speed would be 22.1 m/s
