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Olin [163]
3 years ago
12

As a car drives with its tires rolling freely without any slippage, the type of friction acting between the tires and the road i

s
Physics
1 answer:
Darya [45]3 years ago
5 0
<span>As a car drives with its tires rolling freely without any slippage, the type of friction acting between the tires and the road is kinetic friction.

We exert force to move the object from rest and in this case, static friction works. But, when the object comes in motion, then kinetic friction works. Here, since the car is driving without slipping means, kinetic friction acts on it. Its also called sliding or dynamic friction.</span>
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A triangular plate with base 4 m and height 5 m is submerged vertically in water so that the tip is even with the surface. Expre
Artyom0805 [142]

Answer:

hydrostatic force is 327000.00 N

Explanation:

given data

base =  4 m

height =  5 m

density of water = 1000 kg/m3

to find out

hydrostatic force

solution

we know this is a triangle so we consider here a small strip PQ whoes  area da in with length x and width dy

so area will be

da = base/H × height = base/H × y

so da = x dy = base/H × y dy

and we know pressure = ρ × g × h

here h = y

hydrostatic force = pressure × area

df = (ρ × g × h) × base/H × y dy

now integrate it from 0 to 5 height

f = ρ × g \int_{0}^{5} (h) (base/H)ydy

f = ρ × g \int_{0}^{5} (y) (4/5)ydy

f = ρ × g  ×  4/5  ×  (y^{3} /3)^{5} _0

now put value ρ = 1000 and g = 9.81

f = ρ × g  ×  4/5  ×  (y^{3} /3)^{5} _0

f = 1000 × 9.81  ×  4/5  × (5³/3)

force = 7848 × 41.666667

force = 327000.00 N

hydrostatic force is 327000.00 N

4 0
3 years ago
Read 2 more answers
According to Newton's second law of motion, if we have a rigid, unchanging mass and we observe it accelerating, what must be hap
kkurt [141]

The force is applied to the accelerating object that has a constant mass. Option A is correct.

<h3>What does Newton's second law of motion state?</h3>

The force applied to the object is the product of its mass and acceleration.

F = ma

Where,

F - force

m- mass

a - acceleration

From the equation, the force and the acceleration are in a proportional relation. The mass is not changing as given in the question.

Therefore, the force is applied to the accelerating object that has a constant mass.

Learn more about Acceleration:

brainly.com/question/2437624

8 0
2 years ago
HELP PLEASE ASAP !!!!Question 5 of 15
lesantik [10]
I think the answer is C
6 0
3 years ago
Read 2 more answers
El valor más preciso de la masa de un electron es 9.11*10^-11kg ¿ Cuánto aumentaría la masa de un cuerpo que se carga con -1 c d
chubhunter [2.5K]

Answer:

m = 569.375\times 10^{6}\,kg

Explanation:

Un electrón tiene una carga negativa de 1.6\times 10^{-19}\,C y la masa total es igual al producto del número de electrones y esa carga unitaria. El número de electrones se obtiene al dividir la carga total por la carga unitaria. (An electron has a negative charge of 1.6\times 10^{-19}\,C and the total mass is equal to the product of the qunatity of electrons and such unit charge. The quantity of electrons is found by diving the total charge by the unit charge):

m = \frac{Q}{q} \cdot m_{e}

m = \left(\frac{1\,C}{1.6\times 10^{-19}\,C} \right)\cdot (9.11\times 10^{-11}\,kg)

m = 569.375\times 10^{6}\,kg

7 0
3 years ago
Predict the magnitude of the gravitational force....
Galina-37 [17]

Answer:

a=650.549

b=246.4819

c=38.5261

Explanation:

7 0
2 years ago
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