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lesya692 [45]
3 years ago
5

An insulating rod having linear charge density λ = 40.0 mC/m and linear mass density μ = 0.100 kg/m is released from rest in a u

niform electric field E = 100 V/m directed perpendicular to the rod.
(a) Determine the speed of the rod after it has traveled 2.00 m.
(b) What If

Physics
1 answer:
Nezavi [6.7K]3 years ago
5 0

Answer:

a) Speed of the rod = 0.4m/s

b) The part b says what if ? how does your answer to part (a) change if the electric field is not perpendicular to the rod?

If the electric field is not perpendicular to the rod, then a rrsolution has to be don eon the x -axis by resolving with respect tp Cos theta, the value pf the speed will still remains the same.

Explanation:

The detailed and mathematical derivation is shown in the attachment.

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An electron with a charge of -1.6 × 10-19 coulombs experiences a field of 1.4 × 105 newtons/coulomb. What is the magnitude of th
kipiarov [429]

Answer:

2.24 \times 10^{-14} Newtons

Explanation:

Magnitude of charge on the electron = q = 1.6 \times 10^{-19} Coulombs

The negative sign in the question statement indicates that the charge is negative.

Magnitude of Electric Field experienced by the electron = E = 1.4 \times 10^{5} Newtons/Coulomb

Magnitude of Force on the electron = F = ?

The relation between the charge, electric field and the force on the charge because of electric field is given by:

E=\frac{F}{q}

From here we can write:

F = qE

Using the values, we get:

F = 1.6 \times 10^{-19} \times 1.4 \times 10^{5}\\\\ F = 2.24 \times 10^{-14}

Thus, the magnitude of the electric force experience by the electron would be 2.24 \times 10^{-14} Newtons

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People have proposed driving motors with the earth's magnetic field. This is possible in principle, but the small field means th
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Answer:

Explanation:

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A 500kg elevator is raised to a height of 10 m in 10 seconds. Calculate the power of the motor.
Hunter-Best [27]

Answer:

Correct answer: Third statement  P = 4900 W

Explanation:

Given:

m = 500 kg  the mass of the elevator

h = 10 m  reached height after t = 10 seconds

P = ? power of the motor

The formula for the calculating power of the motor is:

P = W / t

since work is a measure of change in this case of potential energy then it is:

W = ΔEp = Ep - 0 = Ep

In this case we must take g = 9.81 m/s²

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