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lesya692 [45]
3 years ago
5

An insulating rod having linear charge density λ = 40.0 mC/m and linear mass density μ = 0.100 kg/m is released from rest in a u

niform electric field E = 100 V/m directed perpendicular to the rod.
(a) Determine the speed of the rod after it has traveled 2.00 m.
(b) What If

Physics
1 answer:
Nezavi [6.7K]3 years ago
5 0

Answer:

a) Speed of the rod = 0.4m/s

b) The part b says what if ? how does your answer to part (a) change if the electric field is not perpendicular to the rod?

If the electric field is not perpendicular to the rod, then a rrsolution has to be don eon the x -axis by resolving with respect tp Cos theta, the value pf the speed will still remains the same.

Explanation:

The detailed and mathematical derivation is shown in the attachment.

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Consider f(x) = -4x2 + 24x + 3. Determine whether the function has a maximum or minimum value. Then find the
murzikaleks [220]

Answer:

The function has a maximum in x=3

The maximum is:

f(3) = 39

Explanation:

Find the first derivative of the function for the inflection point, then equal to zero and solve for x

f(x)' = -4*2x + 24=0

-4*2x + 24=0

8x=24

x=3

Now find the second derivative of the function and evaluate at x = 3.

If f (3) ''< 0 the function has a maximum

If f (3) '' >0 the function has a minimum

f(x)''= 8

Note that:

f(3)''= -8

the function has a maximum in x=3

The maximum is:

f(3)=-4(3)^2+24(3) + 3\\\\f(3) = 39

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3 years ago
Below is the data from a gas law experiment comparing the pressure and the volume of a gas at a given temperature.
Wewaii [24]

Answer:

The combined gas equation relates three variables pressure, temperature and volume when the number of moles is constant.

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Explanation:

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3 years ago
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A leaf is floating on the Surface of the water,what will happen to its movement? Explain
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Answer:

MRCORRECT has answered the question

Explanation:

surface tension of water helps creatures(mostly of insecta class such as water striders) to walk on water. . it also helps water to move up the xylem tissue ofhigher plants without breaking up

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A satellite omass1000 kg moves in a circular orbit of radius 8000 km round the earth,assumed to be a sphere of radius 6400 km. C
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Answer:

ΔE = 37.8 x 10^9 J

Explanation:

The energy required will increased the potential energy and increase the kinetic energy.

As the altitude change is fairly small compared to the earth radius, we can ASSUME that the average gravity will be a good representative

Gravity acceleration at altitude would be 9.8(6400²/8000²) = 6.272 m/s²

G(avg) = (9.8 + 6.272)/2 = 8.036 m/s²

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v² = (6.272(8.0e6)) = 50.2e6 m²/s²

The maximum velocity when resting on earth at the equator is about 460 m/s.

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A soda has a volume of 560 mL and a density of 3.2 g/mL. What is the mass?
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