An insulating rod having linear charge density λ = 40.0 mC/m and linear mass density μ = 0.100 kg/m is released from rest in a u
niform electric field E = 100 V/m directed perpendicular to the rod.
(a) Determine the speed of the rod after it has traveled 2.00 m.
(b) What If
(a) Determine the speed of the rod after it has traveled 2.00 m.
(b) What If
1 answer:
Answer:
a) Speed of the rod = 0.4m/s
b) The part b says what if ? how does your answer to part (a) change if the electric field is not perpendicular to the rod?
If the electric field is not perpendicular to the rod, then a rrsolution has to be don eon the x -axis by resolving with respect tp Cos theta, the value pf the speed will still remains the same.
Explanation:
The detailed and mathematical derivation is shown in the attachment.
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Answer:
1.08 m/s
Explanation:
This can be solved with two steps, first we need to find the time taken to fall 9.5 m, then we can divide the horizontal distance covered with time taken to calculate the velocity.
Time taken to fall 9.5 m
vertical acceleration = a = 9.8 m/s^2.
vertical velocity = 0, (since there is only horizontal component for velocity, )
distance traveled s = 9.5 m.
Substituting these values in the equation
⇒ t= 1.392 sec
Velocity needed
We know the time taken (1.392 s) to travel 1.5 m,
So velocity = 1.5 m / 1.392 s = 1.08 m/s
hence velocity of the diver must be at least 1.08 m/s