An insulating rod having linear charge density λ = 40.0 mC/m and linear mass density μ = 0.100 kg/m is released from rest in a u
niform electric field E = 100 V/m directed perpendicular to the rod.
(a) Determine the speed of the rod after it has traveled 2.00 m.
(b) What If
(a) Determine the speed of the rod after it has traveled 2.00 m.
(b) What If
1 answer:
Answer:
a) Speed of the rod = 0.4m/s
b) The part b says what if ? how does your answer to part (a) change if the electric field is not perpendicular to the rod?
If the electric field is not perpendicular to the rod, then a rrsolution has to be don eon the x -axis by resolving with respect tp Cos theta, the value pf the speed will still remains the same.
Explanation:
The detailed and mathematical derivation is shown in the attachment.
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Answer:
The answer is below
Explanation:
Given that:
x(t) = at – bt2+c
a) x(t) = at – bt2+c
Substituting a = 1.4 m/s, b = 0.06 m/s2 and c =50 m gives:
x(t) = 1.4t - 0.06t² + 50
At t = 5, x(5) = 1.4(5) - 0.06(5)² + 50 = 55.5 m
At t = 0, x(0) = 1.4(0) - 0.06(0)² + 50 = 50 m
The average velocity (v) is given as:
b) x(t) = 1.4t - 0.06t² + 50
At t = 10, x(10) = 1.4(10) - 0.06(10)² + 50 = 58 m
At t = 0, x(0) = 1.4(0) - 0.06(0)² + 50 = 50 m
The average velocity (v) is given as:
c) x(t) = 1.4t - 0.06t² + 50
At t = 15, x(5) = 1.4(15) - 0.06(15)² + 50 = 57.5 m
At t = 10, x(10) = 1.4(10) - 0.06(10)² + 50 = 58 m
The average velocity (v) is given as: