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Helga [31]
3 years ago
8

A 1000 kg car accelerates from rest at a rate of 10 m/s² for 3 seconds. A) what is the final velocity of the car?

Physics
1 answer:
Lorico [155]3 years ago
5 0

Answer:

Refer to the attachment!~

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When air pressure decreases, the mercury in a barometer _____.
siniylev [52]

Answer:

The mercury in the barometer will go down as there is less air pressing down on the bulb of the barometer to push mercury up.

Explanation:

7 0
3 years ago
1. You push a deak across the room. A force was applied. The object moves as a result of a force.​
FinnZ [79.3K]

Answer:

what is the question?

Explanation:

I'm not sure if this was a question because you gave the answer lol

6 0
3 years ago
The weight of an astronaut plus his space suit on the Moon is only 319 N. How much (in N) do they weigh on Earth?
zheka24 [161]

Answer:

The weight of an astronaut plus his space suit on the Earth is 1,931.69 N.

Explanation:

Newton's second law, called the fundamental law or fundamental principle of dynamics, states that a body accelerates if a force is applied to it. This law indicates that the net force applied on a body is proportional to the acceleration that the body acquires. The constant of proportionality is the mass of the body, so Newton's second law is expressed in the following formula:

F = m*a

Where:

  • F is the net force. It is expressed in Newton (N)
  • m is the mass of the body. It is expressed in kilograms (Kg).
  • a is the acceleration that the body acquires. It is expressed in meters over second squared (m/s²).

The weight of an astronaut plus his space suit on the Moon is only 319 N. Then, being:

  • F= weight= 319 N
  • m= ?
  • a = acceleration of the Moon's gravity, whose value is 1.62 m/s²

you get:

319 N= m* 1.62 m/s²

Solving:

m=\frac{319 N}{1.62 \frac{m}{s^{2} } }

m=196.91 kg

The mass is an invariable quantity, regardless of the planet in which the astronaut plus his space suit on the Moon is, then you have:

  • F= weight= ?
  • m= 196.91 kg
  • a = acceleration of the Earth's gravity, whose value is 9.81 m/s²

replacing in the definition of force:

Weight= 196.91 kg* 9.81 m/s²

Weight= 1,931.69 N

<u><em>The weight of an astronaut plus his space suit on the Earth is 1,931.69 N.</em></u>

6 0
3 years ago
A device has a least count of 0.01m if it measures a length less than 100m the minimum and maximum number of significant figure
Klio2033 [76]

Answer:

C) 1 and 4

Explanation:

Least count is .01 m . If one measures any number between 100 and 99 , it will be like 99.25 or 99.37 m . So number of significant figure will be 4 ( maximum )

The least one can measure is .01 so least number of significant figure possible is 1 .

5 0
3 years ago
In addition to producing images, ultrasound can be used to heat tissues of the body for therapeutic purposes. An emitter is plac
Dafna11 [192]

Answer:

The answer is Yes, the standing wave length with 5 anti-nodes  will be created

Explanation:

To answer this question, we recall the frequencies of standing wave modes in a closed - closed tube of length (L).

The formula will now be:

                    Fₙ =  n ( v/2L)

Where n = n is equal to the number of anti-nodes

and

lambda = 2L/n for standing waves in a closed tube where n is equal to the number of nodes

Now assuming the nodes are :

Where n = 1, 2, 3, 4, 5, ............

Now, we try to make "n" the subject of formula

Fₙ =  n ( v/2L)

So therefore, the number of nodes produced will be

n = 2L Fₙ / v

2 x 0.55 x  10⁻² x 0.7 x 10⁶  / 1540

Calculating the above further, we arrive at = 5.

Now to answer the question,

The answer is Yes, the standing wave length with 5 anti-nodes  will be created

7 0
3 years ago
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