Answer:
We'll have 1.00 mol H2
Explanation:
Step 1: Data given
Number of moles of Mg = 1.00 moles
Step 2: The balanced equation
Mg(s) + H2SO4(aq) → MgSO4(aq) + H2(g)
Step 3: Calculate moles of H2
For 1 mol Mg we need 1 mol H2SO4 to produce 1 mol MgSO4 and 1 mol H2
We'll have 1.00 mol H2
1 mole= 602,200,000,000,000,000,000,000 its just this huge number! =6.022 x 10 to the power of 23. So that's it I guess!
From the chemical formula the total mass of the compound can be determined. The mass of the 1 mole of the compound is its molar mass. The atom by which the molecule is generated, the mass of these atoms are expressed in terms of amu or atomic unit mass, but after formation of a molecule in a particular ratio the mass of each of the atom becomes the total molecular weight of the generated molecule. In this case the molecule posses three atoms X, Y and Z which are in a ratio of 2:2:7. Thus the chemical formula of the compound can be written as
.
So the total mass of the compound in amu is {(2×47)+(2×42)+(7×16)} = {94+84+112}=290 amu.
Thus 1 mole of the compound contains 290 amu or 290 g by mass.
Henceforth 20 gram of the compound is equivalent to (20/290) = 0.068 mole.
English please i cant understand