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Dima020 [189]
3 years ago
11

Which expressions are equivalent to 5(-2k-3)+2k

Mathematics
1 answer:
frozen [14]3 years ago
6 0

Answer:

A would be the correct one

Step-by-step explanation:

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A person has a bag containing quarters and dimes. There are a total of 61 coins in the bag, and the total value of the coins is
77julia77 [94]

Answer:

Q+D = 65, multiply both sides by 2525Q + 25D = 162525Q + 10D = 950  subtract to get            15D = 675               D = 675/15 = 135/3 = 45 dimes               Q = 65-45 = 20 quarters25(20) + 10(45) = 500+450 = 950

6 0
3 years ago
Do this for me pls its mdths
Vadim26 [7]

Answer:

A = -1

B = -3

C = -7

Step-by-step explanation:

See attached image.

5 0
2 years ago
Solve the proportion
mario62 [17]

Answer:

\boxed{\sf x = 5}

Step-by-step explanation:

\sf Solve  \: for  \: x  \: over  \: the  \: real \:  numbers:  \\ \sf \implies  \frac{2}{x - 3}   =  \frac{5}{x}  \\  \\  \sf Take  \: the \:  reciprocal  \: of  \: both \:  sides:  \\ \sf \implies  \frac{x - 3}{2}  =  \frac{x}{5}  \\  \\  \sf Expand  \: out \:  terms \:  of \:  the \:  left  \: hand \:  side:  \\  \\ \sf \implies \frac{x}{2}  -  \frac{3}{2}  =  \frac{x}{5}  \\  \\  \sf Subtract \:  \frac{x}{5}   -  \frac{3}{2}  \: from  \: both  \: sides: \\  \sf \implies \frac{x}{2}  -  \frac{3}{2} - ( \frac{x}{5}   -  \frac{3}{2} ) =  \frac{x}{5} - ( \frac{x}{5}  -  \frac{3}{2} ) \\  \\  \sf \implies \frac{x}{2}  -  \frac{3}{2} -  \frac{x}{5}    +   \frac{3}{2} =  \frac{x}{5} -  \frac{x}{5}  +  \frac{3}{2}  \\  \\  \sf \frac{x}{5}  -  \frac{x}{5}  = 0 :  \\  \sf \implies \frac{x}{2}  -  \frac{x}{5}  -  \frac{3}{2}  +  \frac{3}{2}  =  \frac{3}{2}  \\  \\  \sf  \frac{3}{2}   -   \frac{3}{2}   = 0:  \\  \sf \implies \frac{x}{2}  -  \frac{x}{5}  =  \frac{3}{2}   \\  \\ \sf \frac{x}{2}  -  \frac{x}{5} =  \frac{5x - 2x}{10}  =  \frac{3x}{10} :  \\   \sf \implies \frac{3x}{10}  =  \frac{3}{2}   \\  \\ \sf Multiply \:  both  \: sides \:  by \:  \frac{10}{3}  : \\   \sf \implies \frac{3x}{10}  \times  \frac{10}{3}  =  \frac{3}{2 }  \times  \frac{10}{3}   \\  \\ \sf \frac{3x}{10}  \times  \frac{10}{3}  =   \cancel{\frac{3}{10} } \times( x) \times  \cancel{ \frac{10}{3} } = x :  \\  \sf \implies x =  \frac{3}{2}  \times  \frac{10}{3} \\  \\   \sf  \frac{3}{2}  \times  \frac{10}{3}  = \cancel{ \frac{3}{2} }  \times \cancel{ \frac{3}{2} }  \times 5 :   \\ \sf \implies x = 5

8 0
3 years ago
Please help, show work!!! :))
otez555 [7]
25.59- 9.99= 15.60
15.60/ 0.05 = 312
312 minutes this month
4 0
3 years ago
Given the measures a = 10, b = 40, and A = 30°, how many triangles can possibly be formed?
arlik [135]

Answer:

no triangle can be formed with the given values (i.e 0 triangle).

Step-by-step explanation:

Given;

length of side a, = 10

length of side b, = 40

angle A, = 30°

Apply sine rule to determine the angle of the second side (B);

\frac{sin \ A}{a} = \frac{sin \ B}{b} \\\\\frac{sin \ 30^0}{10} = \frac{sin \ B}{40}\\\\sin \ B = 40(\frac{0.5}{10} )\\\\sin \ B = 2

The maximum sine function is 1, there is no sine function that will be equal to 2, so there is no triangle that can be formed with the given values.

8 0
3 years ago
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