Answer: The ion that contribute to water hardness are:
--> a. Ca2+
--> b. (HCO)3^- and
--> c. Mg2+
While K+ DOES NOT contribute to water hardness.
Explanation:
WATER in chemistry is known as a universal solvent. This is so because it is polar in nature and dissolves most inorganic solutes and some polar organic solutes to form aqueous solutions. It is composed of elements such as hydrogen and oxygen in the combined ratio of 2:1.
Water is said to be HARD if it does not lather readily with soap. There are two types of water hardness:
--> Permanent hardness: This is mainly due to the presence of CALCIUM and MAGNESIUM ions in the form of soluble tetraoxosulphate(VI) and chlorides. These ions are removed by adding washing soda or caustic soda.
--> Temporary hardness: This is due to the presence of calcium HYDROGENTRIOXOCARBONATES. It can be removed by boiling and using slaked lime.
Therefore from the above given ions, Ca2+,(HCO)3^- and Mg2+ contributes to water hardness.
I think there is a lack of information in the given problem above such as the grams of copper sulfate and sodium hydroxide that was used in the experiment. Kindly resubmit the question with the complete details so that we can help you. Thank you.
Answer:
yo gotta be more specific
Answer:
7.68 × 10²⁴
Explanation:
Step 1: Calculate the mass of 1 molecule of the monomer CH₂CHCN
We will get the mass of the monomer by adding the masses of the elements.
mCH₂CHCN = 3 × mC + 3 × mH + 1 × mN
mCH₂CHCN = 3 × 12.01 amu + 3 × 1.01 amu + 1 × 14.01 amu = 53.07 amu
Step 2: Convert the mass of the monomer to grams
We will use the conversion factor 1 amu = 1.66 × 10⁻²⁴ g
53.07 amu × 1.66 × 10⁻²⁴ g/1 amu = 8.81 × 10⁻²³ g
Step 3: Calculate "n"
We will divide the mass of the polymer by the mass of the monomer.
n = 676.8 g / 8.81 × 10⁻²³ g = 7.68 × 10²⁴
