Answer:
<h2>759.48 L</h2>
Explanation:
The new volume can be found by using the formula for Boyle's law which is
Since we are finding the new volume
From the question we have
We have the final answer as
<h3>759.48 L</h3>
Hope this helps you
Answer:
V₁ = 228 mL
Explanation:
There is some info missing. I think this is the original question.
<em>A chemist must prepare 575 mL of 50.0 mM aqueous potassium permanganate (KMnO₄) working solution. He'll do this by pouring out some 0.126M aqueous potassium permanganate stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the potassium permanganate stock solution that the chemist should pour out. Round your answer to 3 significant digits.</em>
<em />
We want to prepare 575 mL (V₂) of a 50.0 mM solution (C₂). To do so, we start, from a stock solution of concentration C₁ = 0.126 M. In order to find the volume V₁ that the chemist should pour out, we will use the dilution rule.
C₁ × V₁ = C₂ × V₂
0.126 M × V₁ = 50.0 mM × 575 mL
0.126 M × V₁ = 50.0 × 10⁻³ M × 575 mL
V₁ = 228 mL
Answer:
A. Chlorine
Explanation:
Chlorine has 17, Hydrogen has 1, Oxygen has 8, Sulfur has 16.
Answer:
Atomic Oribal
Explanation:
There are four basic types of electron orbitals – s, p, d, and f. (Visual representations can be found in the tutorial above.) The s subshell is a spherical orbital which can contain up to two electrons. Each energy level has one s subshell.
