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sammy [17]
3 years ago
11

olivia bought new gym shoes to play volleyball because she kept slipping when she ran in her old shoes. how will the new soles h

elp solve the problem? by increasing her speed to increase friction by adding surface roughness to increase friction by improving aerodynamics to decrease friction by increasing lubrication to decrease friction
Chemistry
2 answers:
oksano4ka [1.4K]3 years ago
8 0
By adding surface roughness to increase friction
mrs_skeptik [129]3 years ago
6 0

The correct answer is by adding surface roughness to increase friction.  

A rough surfaces pair will exhibit more friction in comparison to a pair of smooth surfaces, as the peak of one surface can fall into the valleys of the other, signifying that in order to maintain movement, either something is required to break, or the surfaces would be required to get somewhat push apart.  

Rougher the surfaces, the more commonly hills will have to push apart from each other, and the steeper will be the hills. For the majority of the practical work, friction is caused by the physical roughness of the surfaces taking part.  

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Name of th molecule <br> 1. CH3CH2CHClCHBrCH3<br> 2.C=C-CH3<br> CH3CH=CHCH2
Grace [21]

Answer:

1: 2-bromo-3-chloropentane

Explanation:

find longest carbon chain =5

place the Br and Cl on the carbon chain

follow naming rules I guess

4 0
3 years ago
A molecule contains five atoms and has a molecular weight of 85 g per mole. the atoms are of elements with atomic numbers 1, 6,
inessss [21]

Answer:

            Dichloromethane

Explanation:

As we know the atomic number given belongs to following elements, i.e.

Atomic #                   Element                      M.Mass

   1                           Hydrogen                    1 g.mol⁻¹

   6                          Carbon                        12 g.mol⁻¹

   17                         Chlorine                      35.5 g.mol⁻¹

Also the molecular formula of Dichloromethane is,

                           =  CH₂Cl₂

Putting molar masses of each element,

                          =  (12)₁  +  (1)₂  +  (35.5)₂

                          =  12  +  2  +  71

                          =  85 g.mol⁺¹

Result:

         Hence the only possible structure containing 5 atoms is Dichloromethane.

6 0
4 years ago
Sulfuric acid is produced in larger amounts by weight than any other chemical. It is used in manufacturing fertilizers, oil refi
Fed [463]

Answer:

A. -166.6 kJ/mol

B. -127.7 kJ/mol

C. -133.9 kJ/mol

Explanation:

Let's consider the oxidation of sulfur dioxide.

2 SO₂(g) + O₂(g) → 2 SO₃(g)     ΔG° = -141.8 kJ

The Gibbs free energy (ΔG) can be calculated using the following expression:

ΔG = ΔG° + R.T.lnQ

where,

ΔG° is the standard Gibbs free energy

R is the ideal gas constant

T is the absolute temperature (25 + 273.15 = 298.15 K)

Q is the reaction quotient

The molar concentration of each gas ([]) can be calculated from its pressure (P) using the following expression:

[]=\frac{P}{R.T}

<em>Calculate ΔG at 25°C given the following sets of partial pressures.</em>

<em>Part A  130atm SO₂, 130atm O₂, 2.0atm SO₃. Express your answer using four significant figures.</em>

[SO_{2}]=[O_{2}]=\frac{130atm}{(0.08206atm.L/mol.K).298K} =5.32M

[SO_{3}]=\frac{2.0atm}{(0.08206atm.L/mol.K).298K} =0.0818M

Q=\frac{[SO_3]^{2} }{[SO_{2}]^{2}.[O_{2}] } =\frac{0.0818^{2} }{5.32^{3} } =4.44 \times 10^{-5}

ΔG = ΔG° + R.T.lnQ = -141.8 kJ/mol + (8.314 × 10⁻³ kJ/mol.K) × 298 K × ln (4.44 × 10⁻⁵) = -166.6 kJ/mol

<em>Part B  5.0atm SO₂, 3.0atm O₂, 30atm SO₃  Express your answer using four significant figures.</em>

<em />

[SO_{2}]=\frac{5.0atm}{(0.08206atm.L/mol.K).298K}=0.204M

[O_{2}]=\frac{3.0atm}{(0.08206atm.L/mol.K).298K}=0.123M

[SO_{3}]=\frac{30atm}{(0.08206atm.L/mol.K).298K}=1.23M

Q=\frac{[SO_3]^{2} }{[SO_{2}]^{2}.[O_{2}] } =\frac{1.23^{2} }{0.204^{2}.0.123 } =296

ΔG = ΔG° + R.T.lnQ = -141.8 kJ/mol + (8.314 × 10⁻³ kJ/mol.K) × 298 K × ln 296 = -127.7 kJ/mol

<em>Part C Each reactant and product at a partial pressure of 1.0 atm.  Express your answer using four significant figures.</em>

<em />

[SO_{2}]=[O_{2}]=[SO_{3}]=\frac{1.0atm}{(0.08206atm.L/mol.K).298K}=0.0409M

Q=\frac{[SO_3]^{2} }{[SO_{2}]^{2}.[O_{2}] } =\frac{0.0409^{2} }{0.0409^{3}} =24.4

ΔG = ΔG° + R.T.lnQ = -141.8 kJ/mol + (8.314 × 10⁻³ kJ/mol.K) × 298 K × ln 24.4 = -133.9 kJ/mol

7 0
3 years ago
Elements in group 2 are all called alkaline earth metals. What is most similar about the alkaline earth metals?
german

Answer:

D

Explanation: the last one

4 0
3 years ago
Read 2 more answers
How can I get the percentage recovery?
frosja888 [35]
If you collected 7.0 grams of something the percentage recovery would be 70% (7/10 x 100).
^
^
^
A percentage recovery is something like that
3 0
3 years ago
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