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sammy [17]
3 years ago
11

olivia bought new gym shoes to play volleyball because she kept slipping when she ran in her old shoes. how will the new soles h

elp solve the problem? by increasing her speed to increase friction by adding surface roughness to increase friction by improving aerodynamics to decrease friction by increasing lubrication to decrease friction
Chemistry
2 answers:
oksano4ka [1.4K]3 years ago
8 0
By adding surface roughness to increase friction
mrs_skeptik [129]3 years ago
6 0

The correct answer is by adding surface roughness to increase friction.  

A rough surfaces pair will exhibit more friction in comparison to a pair of smooth surfaces, as the peak of one surface can fall into the valleys of the other, signifying that in order to maintain movement, either something is required to break, or the surfaces would be required to get somewhat push apart.  

Rougher the surfaces, the more commonly hills will have to push apart from each other, and the steeper will be the hills. For the majority of the practical work, friction is caused by the physical roughness of the surfaces taking part.  

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Does the color of bell peppers effect the number of seeds inside? Please someone help ASAP I need it today
Mekhanik [1.2K]

I don't think so. "It's not a matter of pigment discrimination: Red and yellow bell peppers are essentially just green peppers that have been allowed to ripen"

3 0
3 years ago
The concentration of CI ion in a sample of H,0 is 15.0 ppm. What mass of CI ion is present in 240.0 mL of H,0, which has a densi
Doss [256]

Answer:

Mass of solute = 0.0036 g

Explanation:

Given data:

Concentration of Cl⁻ = 15.0 ppm

Volume of water = 240 mL

Mass of Cl⁻ present = ?

Solution:

1 mL = 1 g

240 mL = 240 g

Formula:

ppm = mass of solute / mass of sample ×1,000,000

by putting values,

15.0 ppm = (mass of solute / 240 g) ×1,000,000

Mass of solute = 15.0 ppm ×  240 g / 1,000,000

Mass of solute = 0.0036 g

8 0
3 years ago
I need the answer fast plzzz!! NO LINKS
Arturiano [62]

Answer:

your answer is 12 hope it's correct answer

4 0
3 years ago
What bond vibrations and stretching frequencies should you observe in the IR spectrum of caffeine?
Margarita [4]
  • The bond vibrations that can be observed in the IR spectrum of caffeine :

i) asymmetric, ii) symmetric, iii) wagging, iv) twisting, v) scissoring, vi) rocking

  • while the observable stretching frequencies are ; 1700, 1300, 2900, 1500 and 3000.

Caffeine is a polyatomic molecule ( contains more than two atoms bonded via covalent bonds )  therefore its atoms can vibrate in three dimensions ( x, y, z ).therefore the bond vibrations that can be observed in the IR spectrum of caffeine are :  asymmetric, symmetric, wagging, twisting, scissoring, and rocking.

The observable stretching frequencies that are in the IR spectrum of caffeine ; C = O is 1700 ,  C - H is 1300,  C -H is 2900,  C -N is 1500, and N -H = 3000.

Hence we can conclude The bond vibrations that can be observed in the IR spectrum of caffeine : i) asymmetric, ii) symmetric, iii) wagging, iv) twisting, v) scissoring, vi) rocking and the observable stretching frequencies are ; 1700, 1300, 2900, 1500 and 3000.

Learn more : brainly.com/question/13184210

3 0
2 years ago
A certain amount of H2S was added to a 2.0 L flask and allowed to come to equilibrium. At equilibrium, 0.072 mol of H2 was found
SIZIF [17.4K]

Answer:

0.098 moles H₂S

Explanation:

The reaction that takes place is

  • 2H₂(g) + S₂(g) ⇄ 2H₂S(g)  keq = 7.5

We can express the equilibrium constant as:

  • keq = [H₂S]² / [S₂] [H₂]² = 7.5

With the volume we can <u>calculate the equilibrium concentration of H₂</u>:

  • [H₂] = 0.072 mol / 2.0 L = 0.036 M

<em>The stoichiometric ratio</em> tells us that <u>the concentration of S₂ is half of the concentration of H₂</u>:

  • [S₂] = [H₂] / 2 = 0.036 M / 2 = 0.018 M

Now we <u>can calculate [H₂S]</u>:

  • 7.5 = [H₂S]² / (0.018*0.036²)
  • [H₂S] = 0.013 M

So 0.013 M is the concentration of H₂S <em>at equilibrium</em>.

  • This would amount to (0.013 M * 2.0 L) 0.026 moles of H₂S
  • The moles of H₂ at equilibrium are equal to the moles of H₂S that reacted.

Initial moles of H₂S - Moles of H₂S that reacted into H₂ = Moles of H₂S at equilibrium

Initial moles of H₂S - 0.072 mol = 0.026 mol

Initial moles of H₂S = 0.098 moles H₂S

8 0
3 years ago
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