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sammy [17]
3 years ago
11

olivia bought new gym shoes to play volleyball because she kept slipping when she ran in her old shoes. how will the new soles h

elp solve the problem? by increasing her speed to increase friction by adding surface roughness to increase friction by improving aerodynamics to decrease friction by increasing lubrication to decrease friction
Chemistry
2 answers:
oksano4ka [1.4K]3 years ago
8 0
By adding surface roughness to increase friction
mrs_skeptik [129]3 years ago
6 0

The correct answer is by adding surface roughness to increase friction.  

A rough surfaces pair will exhibit more friction in comparison to a pair of smooth surfaces, as the peak of one surface can fall into the valleys of the other, signifying that in order to maintain movement, either something is required to break, or the surfaces would be required to get somewhat push apart.  

Rougher the surfaces, the more commonly hills will have to push apart from each other, and the steeper will be the hills. For the majority of the practical work, friction is caused by the physical roughness of the surfaces taking part.  

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A 1.800-g sample of solid phenol (C6H5OH(s)) was burned in a bomb calorimeter whose total heat capacity is 11.66 kJ/?C. The temp
vichka [17]

Answer:

The balanced chemical equation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat of combustion per gram of phenol is 32.454 kJ/g

Heat of combustion per gram of phenol is 3,050 kJ/mol

Explanation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat capacity of calorimeter = C = 11.66 kJ/°C

Initial temperature of the calorimeter = T_1= 21.36^oC

Final temperature of the calorimeter = T_2= 26.37^oC

Heat absorbed by calorimeter = Q

Q=C\times \Delta T

Heat released during reaction = Q'

Q' = -Q ( law of conservation of energy)

Energy released on combustion of 1.800 grams of phenol = Q' = -(58.4166 kJ)

Heat of combustion per gram of phenol:

\frac{Q'}{1.800 g}=\frac{-58.4166 kJ}{1.800 g}=32.454 kJ/g

Molar mass of phenol = 94 g/mol

Heat of combustion per gram of phenol:

\frac{Q'}{\frac{1.800 g}{94 g/mol}}=\frac{-58.4166 kJ\times 94 g/mol}{1.800 g}=3,050 kJ/mol

3 0
3 years ago
6. (1 point) What is the correct formula for sodium sulfate? *
Deffense [45]
6) Na2 SO4
7)nonmetallic elements
10)mass
11) mole
* sorry I didn't know Q. 8/9
4 0
3 years ago
Read 2 more answers
As ___ increases,___ increases
Goshia [24]

Answer:

if the force applied increases

if the area of contact increases

Explanation:

8 0
3 years ago
Two 10g blocks, one of copper and one of iron, were heated from 300 K to 400K (a temperature difference of 100 K).
12345 [234]

1) 385 J

2) 450 J

Explanation:

1)

The amount of energy that must be absorbed by a certain substance in order to increase its temperature by \Delta T is given by the equation:

Q=mC\Delta T

where

m is the mass of the substance

C is its specific heat capacity

\Delta T is the increase in temperature of the substance

For the block of copper in this problem, we have:

m = 10 g is the mass

C=0.385 J/gK is the specific heat capacity of copper

\Delta T=400-300 = 100 K is the change in temperature

So, the energy absorbed by the block of copper is

Q=(10)(0.385)(100)=385 J

2)

Similarly for the block of iron, the energy absorbed by the iron is given by

Q=mC\Delta T

where

m is the mass of the block of iron

C is its specific heat capacity of iron

\Delta T is the increase in temperature of the block

Here we have:

m = 10 g is the mass of the block

C=0.450 J/gK is the specific heat capacity of iron

\Delta T=400-300 = 100 K is the change in temperature

So, the energy absorbed by the block of iron is

Q=(10)(0.450)(100)=450 J

6 0
3 years ago
Which is the most important value of a graph
aksik [14]
X and y axis. i think
4 0
3 years ago
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