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aleksandr82 [10.1K]

2 years ago

5

There are four boys and 8 girls on the debate team. the coach randomly chooses 3 of the students to participate in a competition

. what is the probability the coach selects all girls?

1 answer:

makvit [3.9K]2 years ago

3 0

<span>the probability the coach selects all girls is m</span>ost likely

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Convert 5 feet to inches there are 12 inches in 1 foot

ladessa [460]

Answer:

60

Step-by-step explanation:

12*5=60

12 inches in a foot, you have 5 feet so 12*5=60

3 0

2 years ago

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Find the slope of the two points below

earnstyle [38]

Answer:

-3/2

Step-by-step explanation:

Formula for slope is y2-y1/x2-x1

3-5/3-1

-3/2

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2 years ago

There 37 paperclips in a box. carmen places more paper clips in the box. which equation models the total number of paperclips p

Ronch [10]

The first thing we must do for this case is to define variables:
p = total number of paperclips
x = paper clips added by carmen.
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p = x + 37

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2 years ago

Janelys needed to get her computer fixed. She took it to the repair store. The technician at the store worked on the computer fo

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6 0

1 year ago

If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.

Lelechka [254]

Answer:

$\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }$

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

$f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)$

So we can say that

$a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}$

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

$(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab$

and we can notice that

$a^2+b^2=(a+b)^2-2ab$ so

$(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab$

it comes

$x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}$

multiply by 3

$3x^2-20x+2*16+5=3x^2-20x+37$

4 0

2 years ago