Answer:
The bomb will remain in air for <u>17.5 s</u> before hitting the ground.
Explanation:
Given:
Initial vertical height is, 
Initial horizontal velocity is, 
Initial vertical velocity is, 
Let the time taken by the bomb to reach the ground be 't'.
So, consider the equation of motion of the bomb in the vertical direction.
The displacement of the bomb vertically is 
Acceleration in the vertical direction is due to gravity, 
Therefore, the displacement of the bomb is given as:
So, the bomb will remain in air for 17.5 s before hitting the ground.
Just like mass, energy, linear momentum, and electric charge, angular momentum is also conserved.
The wheel has angular momentum. I don't remember whether it's
up or down (right-hand or left-hand rule), but it's consistent with
counterclockwise rotation as viewed from above.
When you grab the wheel and stop it from spinning (relative to you),
that angular momentum has to go somewhere.
As I see it, the angular momentum transfers through you as a temporary
axis of rotation, and eventually to the merry-go-round. Finally, all the mass
of (merry-go-round) + (you) + (wheel) is rotating around the big common
axis, counterclockwise as viewed from above, and with the magnitude
that was originally all concentrated in the wheel.
Answer:
The time-interval of the collision is 
Explanation:
As given the force is equal to the rate of change of momentum. Mathemticaly this is:
We can rearrange this equation to solve for 
which gives
which is our answer.
In words this means the time interval is equal to the momentum change in that interval divided by the force applied that caused this momentum change.
The current in the 50 Ω resistor is A) 1.2 A
Answer:
on edge the answer is B Spectrometer
Explanation:
