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Dmitry_Shevchenko [17]
3 years ago
14

The magnitude of the force involved in a certain collision (measured in newtons) is equal to the change in momentum (measured in

kilogram meters/second). What is the time interval of the collision?
Physics
1 answer:
Vinvika [58]3 years ago
4 0

Answer:

The time-interval of the collision is t=\frac{{\Delta}p}{F}

Explanation:

As given the force is equal to the rate of change of momentum. Mathemticaly this is:

F=\frac{dp}{dt}.

We can rearrange this equation to solve for {\delta}t which gives

t=\frac{{\Delta}p}{F}

which is our answer.

In words this means the time interval is equal to the momentum change in that interval divided by the force applied that caused this momentum change.

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ke=½mv²

½×3500×12²=3500×144÷2

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Briefly describe the characteristics of each soil horizon from the top layer to the bottom layer
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3 years ago
Read 2 more answers
Se lanza una pelota de béisbol desde la azotea de un edificio de 25 m de altura con velocidad inicial de magnitud 10 m/s y dirig
MissTica

Answer:

 v_f = 24.3 m / s

Explanation:

A) In this exercise there is no friction so energy is conserved.

Starting point. On the roof of the building

         Em₀ = K + U = ½ m v₀² + m g y₀

Final point. On the floor

         Em_f = K = ½ m v_f²

         Emo = Em_g

         ½ m v₀² + m g y₀ = ½ m v_f²

        v_f² = v₀² + 2 g y₀

         

let's calculate

        v_f = √(10² + 2 9.8 25)

        v_f = 24.3 m / s

6 0
3 years ago
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