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Mila [183]
3 years ago
7

What is the cube root of -1000p^12q^3

Mathematics
2 answers:
Umnica [9.8K]3 years ago
7 0
∛(<span>-1000p^12q^3) 
= -10p^4 q

Hope it helps</span>
iragen [17]3 years ago
7 0

Answer:

-10p^4q

Step-by-step explanation:

Using the exponent rules:

\sqrt[n]{a^n} = a

\sqrt[3]{-1} = -1

To find the cube root of :

-1000p^{12}q^3

then;

\sqrt[3]{-1000p^{12}q^3}

We can write :

1000 = 10 \cdot 10 \cdot 10 = 10^3

p^{12} = (p^4)^3

then;

\sqrt[3]{-10^3 \cdot (p^4)^3 \cdot q^3}

Apply the exponent rules:

-10 \cdot p^4 \cdot q

⇒-10p^4q

Therefore, the cube root of -1000p^{12}q^3 is, -10p^4q

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b)

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  b = 3 and hypotenuse c = 5

Given ΔABC  is a right angle triangle

By using pythagoras theorem

        c² = a² + b²

  ⇒ a² = c² - b²

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          =25 - 9

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⇒   a = √16 = 4

The sides of right angle triangle  a = 4 ,b = 3 and c = 5

<u><em>Step(ii):-</em></u>

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

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3 years ago
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