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Mila [183]
3 years ago
7

What is the cube root of -1000p^12q^3

Mathematics
2 answers:
Umnica [9.8K]3 years ago
7 0
∛(<span>-1000p^12q^3) 
= -10p^4 q

Hope it helps</span>
iragen [17]3 years ago
7 0

Answer:

-10p^4q

Step-by-step explanation:

Using the exponent rules:

\sqrt[n]{a^n} = a

\sqrt[3]{-1} = -1

To find the cube root of :

-1000p^{12}q^3

then;

\sqrt[3]{-1000p^{12}q^3}

We can write :

1000 = 10 \cdot 10 \cdot 10 = 10^3

p^{12} = (p^4)^3

then;

\sqrt[3]{-10^3 \cdot (p^4)^3 \cdot q^3}

Apply the exponent rules:

-10 \cdot p^4 \cdot q

⇒-10p^4q

Therefore, the cube root of -1000p^{12}q^3 is, -10p^4q

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<em>Additional comment</em>

You can also make the correct choice by evaluating the equation at a couple of different values of x. Convenient ones are x= -1, or 0, or +1. The value at x=0 is the y-intercept, (0, -2), which seems to be a point on all of the graphs. The value at x=1 is 3/2+4-2 = 3.5, which looks like it is only seen on graph A.

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