Answer:
The new partial pressures after equilibrium is reestablished for :
The new partial pressures after equilibrium is reestablished :
The new partial pressures after equilibrium is reestablished for :
Explanation:
At equilibrium before adding chlorine gas:
Partial pressure of the
Partial pressure of the
Partial pressure of the
The expression of an equilibrium constant is given by :
At equilibrium after adding chlorine gas:
Partial pressure of the
Partial pressure of the
Partial pressure of the
Total pressure of the system = P = 263.0 Torr
At initail
(13.2) Torr (32.8) Torr (13.2) Torr
At equilbriumm
(13.2-x) Torr (32.8-x) Torr (217.0+x) Torr
Solving for x;
x = 6.402 Torr
The new partial pressures after equilibrium is reestablished for :
The new partial pressures after equilibrium is reestablished :
The new partial pressures after equilibrium is reestablished for :
Answer:
295 mL
Explanation:
Given data:
Volume needed = ?
Molarity of solution = 0.193 M
Mass of salt = 7.90 g
Solution:
Molarity = number of moles of solute / volume in L
Number of moles of salt = mass/molar mass
Number of moles of salt = 7.90 g/ 138.205 g/mol
Number of moles = 0.057 mol
Volume needed:
Molarity = number of moles / volume in L
0.193 M = 0.057 mol / volume in L
Volume in L = 0.057 mol / 0.193 M
Volume in L = 0.295 L
L into mL
0.295 L × 1000 mL/1L
295 mL
Answer:
The vapor pressure of the solution is 3.69 torr
Explanation:
Step 1: Data given
Mole fraction of benzene in the solution = 0.139
P° of benzene is 26.5 torr
Step 2: Calculate the vapor pressure of the solution
Psolution = Xbenzene * P°benzene
⇒with Psolution = the vapor pressure of the solution
⇒with Xbenzene = the mole fraction of benzene = 0.139
⇒with P°benzene = the vapor pressure of pure benzene = 26.5 torr
Psolution = 0.139 * 26.5 torr
Psolution = 3.69 torr
The vapor pressure of the solution is 3.69 torr
Answer:
Write this in a word and skeleton equation:
Solid silver chloride and an aqueous solution of nitric acid are produced when a solution of silver nitrate is reacted with a solution of hydrochloric acid.
Explanation: