Two samples of hot unknown metals of equal temperatures are dropped in separate containers of water at 30 degrees Celsius. The f
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Answer:
<h3>The answer is 8.40 g/mL</h3>Explanation:
The density of a substance can be found by using the formula
volume = final volume of water - initial volume of water
volume = 56.4 - 50 = 6.4 mL
We have
We have the final answer as
<h3>8.40 g/mL</h3>Hope this helps you
Answer
pH=8.5414
Procedure
The Henderson–Hasselbalch equation relates the pH of a chemical solution of a weak acid to the numerical value of the acid dissociation constant, Kₐ. In this equation, [HA] and [A⁻] refer to the equilibrium concentrations of the conjugate acid-base pair used to create the buffer solution.
pH = pKa + log₁₀ ([A⁻] / [HA])
Where
pH = acidity of a buffer solution
pKa = negative logarithm of Ka
Ka =acid disassociation constant
[HA]= concentration of an acid
[A⁻]= concentration of conjugate base
First, calculate the pKa
pKa=-log₁₀(Ka)= 8.6383
Then use the equation to get the pH (in this case the acid is HBrO)