<span>There are a number of ways
to express concentration of a solution. This includes molarity. It is
expressed as the number of moles of solute per volume of the solution. To convert the mass of the solute to moles, we use the molar mass of the substance. We calculate as follows:
MOlarity = 4.725 g ( 1 mol / 58.45 g ) / .5 L = 0.162 mol / L</span>
Runoff (Hope this helped)
Cu (s) + 2AgNO3 ---> 2Ag + Cu(NO3)2
=13.5 moles Silver Nitrate
Answer:
The molarity of the final solution is 1.7 M
Explanation:
The parameters given are;
First solution = 400 ml of 1.25 M
Second solution = 300 ml of 2.30 M
Therefore, we have;
First solution contains 400/1000 * 1.25 moles = 0.5 moles of the substance
Second solution contains 300/1000 * 2.30 moles = 0.69 moles of the
Hence the sum of the two solutions contains 0.5 + 0.69 = 1.19 moles of the substance
The volume of the sum of the two solutions = 400 ml + 300 ml = 700 ml
Hence we have the concentration of the final solution presented as follows;
700 ml contains 1.19 moles of the substance
Therefore;
1000 ml will contain 1000/700 * 1.19 = 1.7 moles
The molarity of the final solution = The number of moles per 1000 ml = 1.7 M.
Any solute that dissolves in water to give a solution that contains ions, and which therefore conducts electricity, is called an electrolyte. On the other hand, a solute that remains undissociated in solution is called a nonelectrolyte.
