The structure of graphite and diamond come under what structure

Caffeine, a molecule found in coffee, tea, and certain soft drinks, contains C, H, O, and N. Combustion of 10.0 g of caffeine pr

denis-greek [22]

Answer:

194 g/mol.

Explanation:

Hello,

In this case, one first must compute the mass of each element as shown below:

$C=18.13gCO_2*\frac{12gC}{44gCO_2} =4.945gC\\H=4.639gH_2O*\frac{2.016gH}{18.0152gH_2O}=0.519gH\\N=2.885gN_2\\O=10.0g-4.945g-0.519g-2.885g=1.651gO$

Next, the corresponding moles:

$C=4.945gC*\frac{1molC}{12gC}=0.412mol\\H=0.519gH*\frac{1molH}{1gH}=0.519mol\\N=2.885gN*\frac{1molN}{14gN}=0.206molN\\O=1.648gO*\frac{1molO}{16gO} =0.103molO$

Then, each element's subscripts is found to be:

$C=\frac{0.412}{0.103}=4\\H=\frac{0.519}{0.103}=5\\N=\frac{0.206}{0.103} =2\\O=\frac{0.103}{0.103}=1$

Therefore, the empirical formula is:

$C_4H_5N_2O$

Nonetheless, it has a molar mass of 97bg/mol, thereby, by multiplying such formula by 2 one gets:

$C_8H_10N_4O_2$

Which has a molar mass of 194 g/mol being correctly contained in the given interval.

Best regards.

8 0

3 years ago

Which image exclusively represents the principle of radiation? A) IV B) III C) II D) I

arsen [322]

The principle of radiation protection is to trigger deterministic and stochastic effect.

Explanation:

The main aim of principle of radiation is to prevent the deterministic effects of radiation and reduce the risks of stochastic effects.

There are three general principals of radiation used for dealing with ionising radiation are Justification, Dose limitation and Optimization.

The three basic radiation principles are time, distance and shielding.

The risk of exposure to radiation is measured using the conventional unit rem or SI unit (sievert).

4 0

3 years ago

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what electronic transition in a hydrogen atom starting from n=7 energy level will produce infrared radiation with energy of 55.1

Lostsunrise [7]

Answer:

(n = 7) ⟶ (n = 4)

Explanation:

1. Convert the energy to joules per mole of electrons.

E = 55.1 × 1000 = 55 100 J/mol

2. Convert the energy to joules per electron

E = 55 100/(6.022 × 10²³)

E = 9.150 × 10⁻²⁰ J/electron

3. Use the Rydberg equation to calculate the transition

Rydberg's original formula was in terms of wavelengths, but we can rewrite it to have the units of energy. The formula then becomes

$\Delta E = R_{\text{H}} (\frac{ 1}{ n_{f}^{2}} - \frac{ 1}{ n_{i}^{2}})$

where

$R_{\text{H}}$ = the Rydberg constant = 2.178 × 10⁻¹⁸ J

$n_{i}$ and $n_{f}$ are the initial and final energy levels.

$9.150 \times 10^{-20} = 2.178 \times 10^{-18}(\frac{ 1}{ n_{f}^{2}} - \frac{ 1}{ 7^{2}})$

$\frac{9.150 \times 10^{-20} }{2.178 \times 10^{-18}} = \frac{ 1}{ n_{f}^{2}} - \frac{ 1}{ 49}$

$\frac{ 1}{ n_{f}^{2}} = \text{0.042 01} + \frac{1 }{49 }$

$\frac{ 1}{ n_{f}^{2}} = \text{0.042 01 + 0.020 41}$

$\frac{ 1}{ n_{f}^{2}} = \text{0.062 42}$

$n_{f}^{2} = \frac{1 }{ \text{0.062 42}}$

$n_{f}^{2} = 16.02$

$n_{f} = \sqrt{16.02}$

$n_{f} = 4.003 \approx 4$

4 0

3 years ago

MULTIPLE CHOICE QUESTION

Tpy6a [65]

They get closer together

7 0

3 years ago

How much energy will a sample of copper alloy ( 63.0 g) lose if it is cooled from 48.0° to 23.0°C ?

Ymorist [56]

Answer:

Heat lost would be 606.375J

Explanation:

Mass = 63.0g

T1 = 48°C

T2 = 23°C

Specific heat capacity of copper (c) = 0.385J/g°C

Q = Mc∇T

Q = Mc(T₂ - T₁)

Q = 63 * 0.385 * (23 - 48)

Q = 24.255 * -25

Q = -606.375J

The heat lost would be 606.375J

4 0

3 years ago

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