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konstantin123 [22]
3 years ago
5

Base your answer on The circuit diagram below which represents a circuit consisting of two resistors connected to a source of po

tential difference.
What is the total resistance of this circuit?


A)
5

B)
10

C)
20

D)
30
Physics
1 answer:
brilliants [131]3 years ago
8 0
Is the total resistance of this circuit the answer is a C
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at 20 c a length of copper wire has a resistance of 5.0. What is its resistance when the wire is heated to 80c? let a=.0004 at 2
AysviL [449]

Answer:

R=5.12\ \Omega

Explanation:

<u>Electric Resistance and Temperature </u>

For some materials, resistivity is linearly related to the temperature. The function that relates them is

R=R_o[1+\alpha (T-T_o)]

Where Ro is the electric resistance at 20°C, \alpha is the temperature coefficient of the conductor, T is the actual temperature at which we want to compute R, and To is the initial temperature, usually 20°C.

The problem gives us the following values

R_o=5\ \Omega,\ T_o=20^oC,\ \alpha=0.0004\ ^oC^{-1},\ T=80^oC

Thus

R=5[1+0.0004 (80-20)]=5.12\ \Omega

\boxed{R=5.12\ \Omega}

6 0
4 years ago
Can someone give me some tips of how to study. I have already tried writing everything in my lesson but it doesn't seem to work
larisa [96]
Highlighter, color coding sections that go together, flash cards, relaxing with someone while they read out questions ( this will help with testing anxiety too). If you get distracted easily use games to study or small sayings instead of the usual white and black sheet of paper.
3 0
3 years ago
What is the resultant force of the free body diagram?
GaryK [48]

1) Magnitude of the net force: 20.8 N

2) Angle: 35.2^{\circ} clockwise from positive x-direction

Explanation:

1)

First of all, we need to find the components of the resultant force along the horizontal and vertical direction.

We observe that there are two forces acting along the horizontal direction:

F_1=33 N\\F_2 = 16 N

We notice that they act in opposite directions, so the net force in the horizontal direction is the difference between these two forces:

F_x =F_1-F_2=33-16=17 N (to the right)

Instead, there is only one force acting in the vertical direction, so the net force in the vertical direction is:

F_y=F_3=12 N (downward)

Therefore, the magnitude of the net force can be found by using Pythagorean's theorem:

F=\sqrt{F_x^2+F_y^2}=\sqrt{17^2+12^2}=20.8 N

2)

Now we have to find the angle of the resultant net force. We can do it by using the following equation:

tan \theta = \frac{F_y}{F_x}

where

\theta is the angle, measured as clockwise from the positive x-direction (because the vertical net force is downward)

F_y = 12 N is the vertical net force

F_x=17 N is the horizontal net force

Solving, we find:

tan \theta=\frac{12}{17}=0.706

And so the angle is

\theta=tan^{-1}(0.706)=35.2^{\circ}

In a direction down with respect to the right.

Learn more about forces:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

About addition of vectors:

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

4 0
3 years ago
A projectile is launched at an angle 60° to the horizontal
Katena32 [7]

Explanation:

We have,

A projectile is launched at an angle 60° to the horizontal  with some initial speed 45 m/s.

The cliff is 265 m high.

(A) The final velocity of the projectile is given by :

v_f^2-v_i^2=2gs\\\\v_f^2=2gs+v_i^2\\\\v_f^2=2\times 9.8\times 265+45^2\\\\v_f=84.96\ m/s

(B) The maximum height of the projectile is given by :

H=\dfrac{v_i^2\sin^2\theta}{2g}\\\\H=\dfrac{45^2\times \sin^2(60)}{2\times 9.8}\\\\H=77.48\ m

(C) The  horizontal range of the motion is given by :

R=\dfrac{v_i^2\sin 2\theta}{g}\\\\R=\dfrac{(45)^2\times \sin 2(60)}{9.8}\\\\R=178.94\ m

7 0
4 years ago
Which of the following is false?
stealth61 [152]
The correct answer is C
3 0
4 years ago
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