Answer:
Part a: When the road is level, the minimum stopping sight distance is 563.36 ft.
Part b: When the road has a maximum grade of 4%, the minimum stopping sight distance is 528.19 ft.
Explanation:
Part a
When Road is Level
The stopping sight distance is given as

Here
- SSD is the stopping sight distance which is to be calculated.
- u is the speed which is given as 60 mi/hr
- t is the perception-reaction time given as 2.5 sec.
- a/g is the ratio of deceleration of the body w.r.t gravitational acceleration, it is estimated as 0.35.
- G is the grade of the road, which is this case is 0 as the road is level
Substituting values

So the minimum stopping sight distance is 563.36 ft.
Part b
When Road has a maximum grade of 4%
The stopping sight distance is given as

Here
- SSD is the stopping sight distance which is to be calculated.
- u is the speed which is given as 60 mi/hr
- t is the perception-reaction time given as 2.5 sec.
- a/g is the ratio of deceleration of the body w.r.t gravitational acceleration, it is estimated as 0.35.
- G is the grade of the road, which is given as 4% now this can be either downgrade or upgrade
For upgrade of 4%, Substituting values

<em>So the minimum stopping sight distance for a road with 4% upgrade is 528.19 ft.</em>
For downgrade of 4%, Substituting values

<em>So the minimum stopping sight distance for a road with 4% downgrade is 607.59 ft.</em>
As the minimum distance is required for the 4% grade road, so the solution is 528.19 ft.
Distance = speed / time
speed = 95 m/s
time = 3 s
distance = 95 / 3 m
displacement = 95/3 m or 32 m (2 s.f.)
The answer is D.) *Five*
The five factors include: Muscular strength, Muscular endurance, Cardiovascular endurance, flexibility, and body fat composition
Answer:
90 A
Explanation:
Applying,
P = VI.............. Equation 1
Where P = Power, V = Supply voltage, I = current.
Make I the subject of the equation
I = P/V.............. Equation 2
From the question,
Assuming the Voltage of the main electric supply is 120 V
Given: P = 10.8 kW = 10800 W, V = 120 V (household voltage)
Substitute these values into equation 2
I = 10800/120
I = 90 A
Answer:
B = 0.15 T
Explanation:
To find the magnitude of the magnetic field you use the following formula:
( 1 )
m: mass of the electron = 9.1*10^-31 kg
v: velocity of the electron = 3*10^6 m/s
q: charge = 1.6*10^-19
r: radius = 0.11mm = 0.11*10^-3 m
You replace the values of the parameters in the equation (1).

the magnetic field has a magnitude of 0.15 T