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ziro4ka [17]
3 years ago
11

If you wanted to make .5 L of a 1 mole/L (M) of MgSO4 solution, how many grams of MgSO4 would you use?

Chemistry
1 answer:
tino4ka555 [31]3 years ago
8 0

Answer:

0.5 grams

Explanation:

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A certain liquid X has a normal boiling point of 118.4 °C and a boiling point elevation constant K=2.40 °С kg-mol-1. A solution
gizmo_the_mogwai [7]

Answer:

43.47 g

Explanation:

The <em>boiling point elevation</em> is described as:

  • ΔT = K * m

Where ΔT is the difference in boiling points: 120.6-118.4 = 2.2 °C

K is the boiling point elevation constant, K= 2.40 °C·kg·mol⁻¹

and m is the molality of the solution (molality = mol solute/kg solvent).

So first we <u>calculate the molality of the solution</u>:

  • ΔT = K * m
  • 2.2 °C = 2.40 °C·kg·mol⁻¹ * m
  • m=0.917 m

Now we calculate the moles of benzamide (C₇H₇NO, MW=315g/mol), using the given mass of the liquid X.

  • 150 g ⇒ 150/1000 = 0.150 kg
  • 0.917 m = molC₇H₇NO / 0.150kg
  • molC₇H₇NO = 0.138 mol

Finally we convert moles of C₇H₇NO into grams, using its molecular weight:

  • 0.138 molC₇H₇NO * 315g/mol = 43.47 g
4 0
3 years ago
Which properties are examples of chemical properties? Check all that apply.
Scorpion4ik [409]

Answer:

1.Reactivity

2.combustibility

3.Shape

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Explanation:

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Answer: A Covalent Bond

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Name the elements present in the following compounds sodium bromide zinc sulphide lead oxide magnesium nitride potassium iodine

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_____ is the measurement of the density of a substance as compared to water.
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