Computers represent color by combining the sub-colors red, green, and blue (rgb). Each sub-color's value can range from 0 to 255
. Thus (255, 0, 0) is bright red, (130, 0, 130) is a medium purple, (0, 0, 0) is black, (255, 255, 255) is white, and (40, 40, 40) is a dark gray. (130, 50, 130) is a faded purple, due to the (50, 50, 50) gray part. (In other words, equal amounts of red, green, blue yield gray). Given values for red, green, and blue, remove the gray part.
1 answer:
Answer:
Purple without gray part is (80,0,80)
Explanation:
Faded purple is represented by the rgb values (130,50,130), that is to say, 130 red, 50 green and 130 blue. Now we need to remove the gray part which is represented by rgb values (50,50,50). Removing it from the faded purple is carried out by subtracting 50 from each one its rgb values. That is to say the the color without the gray part would be (80,0,80). Attached you will see both purple colors with their respective rgb values.
You might be interested in
Answer:
In Btu:
Q=0.001390 Btu.
In Joule:
Q=1.467 J
Part B:
Temperature at midpoint=274.866 C
Explanation:
Thermal Conductivity=k=30 (Btu/hr)/(ft ⋅ °F)=
Thermal Conductivity is SI units:
Length=20 cm=0.2 m= (20*0.0328) ft=0.656 ft
Radius=4/2=2 mm =0.002 m=(0.002*3.28)ft=0.00656 ft
T_1=500 C=932 F
T_2=50 C= 122 F
Part A:
In Joules (J)
Heat Q is:
In Btu:
Heat Q is:
PArt B:
At midpoint Length=L/2=0.1 m
On rearranging: