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2 years ago

Zachary finished an internship as a Software Quality Assurance Engineer. For which job is he best qualified?

Engineering

2 answers:

astra-53 [7]2 years ago

6 0

Answer:

B. A software development firm needs someone to find and fix bugs on multiple computer platforms.

Explanation:

A software quality assurance engineer is someone who monitors every phase of the software development process so as to ensure design quality, making sure that the software adheres to the standards set by the development company. Finding bugs would make this intern a amazing bug finder

garik1379 [7]2 years ago

4 0

The answer is b hope it helps

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Are spheroidized steels considered as composite? If so, what is the dispersed phase a)- No b)- Yes, Chromium Carbides c)- Yes, I

Kruka [31]

Answer: c)-Yes, spheroidized steel are considered as composite.the dispersed phase is iron carbide.

Explanation: Spheroidized steel are the alloy that have iron as the basic part that have been heat treated to increase their ductility and malleability property .They are considered as composite because they are made up of iron alloys. The heat treatment is usually for the carbon steel and so the dispersed phase that is obtained is iron carbide.

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3 years ago

18. Bela is doing a continuity test. What's he checking?

murzikaleks [220]

Answer:

the bela is doing a continuity test he checking current

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2 years ago

To understand the concept of moment of a force and how to calculate it using a scalar formulation.

AysviL [449]

Answer:

When analyzing forces in a structure or machine, it is conventional to classify forces as external forces;

constraint forces or internal forces.

External forces arise from interaction between the system of interest and its surroundings.

Examples of external forces include gravitational forces; lift or drag forces arising from wind loading;

electrostatic and electromagnetic forces; and buoyancy forces; among others. Force laws governing these

effects are listed later in this section.

Constraint forces are exerted by one part of a structure on another, through joints, connections or contacts

between components. Constraint forces are very complex, and will be discussed in detail in Section 8.

Internal forces are forces that act inside a solid part of a structure or component. For example, a stretched

rope has a tension force acting inside it, holding the rope together. Most solid objects contain very

complex distributions of internal force. These internal forces ultimately lead to structural failure, and also

cause the structure to deform. The purpose of calculating forces in a structure or component is usually to

deduce the internal forces, so as to be able to design stiff, lightweight and strong components. We will

not, unfortunately, be able to develop a full theory of internal forces in this course – a proper discussion

requires understanding of partial differential equations, as well as vector and tensor calculus. However, a

brief discussion of internal forces in slender members will be provided in Section 9.

Explanation:

7 0

2 years ago

A piston-cylinder device contains 0.15 kg of air initially at 2 MPa and 350 °C. The air is first expanded isothermally to 500 kP

Semmy [17]

Answer:

Isothermal expansion W₁ =-37198.9 J

Polytropic Compression W₂ =-34872.82 J

Isobaric Compression W₃ = -6974.566 J

The net work for the cycle = -79046.29 J

Explanation:

Mass of air = 0.15 kg = 150 g

Molar mass = 28.9647 g/mol

Number of moles = 150 g /28.9647 g/mol = 5.179 moles of air

PV = nRT therefrore V = nRT/(P) = 5.179*8.314*(350+273.15)/(2×10⁶) = 0.0134167 m³

For isothermal expansion we have

P₁V₁ = P₂V₂ or V₂ = P₁V₁/P₂ = 2×10⁶*0.0134167 / (5×10⁵) = 0.0536668 m³

Therefore work done

W₁ = -nRTln(V₂/V₁) = -26833ln(4) = -37198.9 J

Stage 2

Compression polytropically we have

$\frac{P_2}{P_3} = (\frac{V_3}{V_2} )^n$ where P₃ = 2 MPa

Therefore V₃ = $(\frac{1}{4} )^{\frac{1}{1.2} }*V_2$ = 1.6904×10⁻² m³

Work = W₂ = $\frac{P_2V_2-P_3V_3}{n-1}$ = -34872.82 J

$\frac{P_2}{P_3} = (\frac{T_2}{T_3} )^\frac{n}{n-1}$ or T₃ = $T_2*(\frac{P_3}{P_2})^\frac{n-1}{n}$ = 785.12 K

Isobaric compression we have thus

Work done W₃ = P(V₁ -V₃) = -6974.566 J

Total work = W₁ + W₂ + W₃ = -37198.9 J + -34872.82 J + -6974.566 J = -79046.29 J

7 0

2 years ago

An actual vapour compression system comprises following process represents a. 1-2 Compression process b. 2-3 Condens 1 (or heat

Gemiola [76]

Answer:

Explanation:

The deatailed diagram of VCRS is given below such

1-2=Isentropic compression in which temperature increases at constant entropy

2-3=Isobaric heat rejection i.e. heat rejected at constant pressure(condensation)

3-4=Irreversible expansion or throttling in which enthalpy remains constant

4-1=Isobaric heat addition(Evaporation)

4 0

2 years ago