3 years ago

A 132mm diameter solid circular section

Engineering

1 answer:

Ganezh [65]3 years ago

5 0

Answer:

not sure if this helps but

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Two metallic terminals protrude from a device. The terminal on the left is the positive reference for a voltage called vx (the o

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Answer:

Vx = 6.242 x 10raised to power 15

Vy = -6.242 x 10raised to power 15

Explanation:

from E = IVt

but V = IR from ohm's law and Q = It from faraday's first law

I = Q/t

E = Q/t x V x t = QV

hence, E =QV

V = E/Q

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3 years ago

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If 1 uF capacitor is fully charged with 120 V across it, how much energy is stored in it? (a) 7.2 kJ (b) 7.2 mJ (c) 0.12 mJ (d)

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(b) 7.2 mJ

Explanation:

ENERGY STORED IN CAPACITOR: the energy is stored in capacitor in electric field

which can be calculated by expressions

E= $\frac{1}{2}$ c $v{^2}$

= $\frac{1}{2}$ $10^{-6}$ $120^{2}$

=7200× $10^{-6}$ J

= 7.2× $10^{-3}$ J

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2 years ago

A part made from annealed AISI 1018 steel undergoes a 20 percent cold-work operation. Obtain the yield strength and ultimate str

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Answer:

yield strength before cold work = 370 MPa

yield strength after cold work = 437.87 MPa

ultimate strength before cold work = 440 MPa

ultimate strength after cold work = 550 MPa

Explanation:

given data

AISI 1018 steel

cold work factor W = 20% = 0.20

to find out

yield strength and ultimate strength before and after the cold-work operation

solution

we know the properties of AISI 1018 steel is

yield strength σy = 370 MPa

ultimate tensile strength σu = 440 MPa

strength coefficient K = 600 MPa

strain hardness n = 0.21

so true strain is here ∈ = $ln\frac{1}{1-0.2}$ = 0.223

yield strength after cold is

yield strength = $K \varepsilon ^n$

yield strength = $600*0.223^{0.21)$

yield strength after cold work = 437.87 MPa

and

ultimate strength after cold work is

ultimate strength = $\frac{\sigma u}{1-W}$

ultimate strength = $\frac{440}{1-0.2}$

ultimate strength after cold work = 550 MPa

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3 years ago

Water at 20 °C is flowing with velocity of 0.5 m/s between two parallel flat plates placed 1 cm apart. Determine the distances f

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Answer:

The distance from the entrance at which the boundary layers meet is 0.516m

The distance from the entrance at which the thermal boundary layers meet is 1.89m

Explanation:

For explanation, look at the attached file

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2 years ago

The term _______________refers to the science of using fluids to perform work.

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The term is hydraulics.

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3 years ago

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A 132mm diameter solid circular section​

A 132mm diameter solid circular section