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S_A_V [24]
3 years ago
6

52 is what percent of 260​

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
3 0

if we take 260 to be the 100%, what is 52 off of it as a percentage?

\bf \begin{array}{ccll} amount&\$\\ \cline{1-2} 260&100\\ 52&x \end{array}\implies \cfrac{260}{52}=\cfrac{100}{x}\implies 5=\cfrac{100}{x} \\\\\\ 5x=100\implies x = \cfrac{100}{5}\implies x=20

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when making a peanut butter and jelly sandwich, 96% of people put the peanut butter on first. write 96% as a decimal.
ikadub [295]
Drop the percent sign so that you only have 96 then divide by 100 to get the decimal (or move the decimal place to the left two).


96% --- drop the percent
96 ----- move the decimal place over to or divide by 100


96/100
96.0


.96
3 0
3 years ago
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Which number below best represents a gain of $4.88?
Flura [38]

Answer: A. 4.88

Step-by-step explanation:

4.88 is positive. It doesnt make sense for the answer to be a negative number when the question is asking for a GAIN of something.

6 0
3 years ago
g find the 2 components of vector b = 2i + j - 3k, one parallel to a = 3i - j and another one perpendicular to a
nika2105 [10]

Answer:

The components of \vec{b} parallel and perpendicular to \vec {a} are \vec {b}_{\parallel} = \frac{3}{2}\,i-\frac{1}{2}\,j and \vec b _{\perp} = \frac{1}{2}\,i+\frac{3}{2}\,j-3\,k, respectively.

Step-by-step explanation:

Let be \vec b = 2\,i+j-3\,k and \vec a = 3\,i-j, the component of \vec b parallel to \vec a is calculated by the following expression:

\vec b_{\parallel} = (\vec b \bullet \hat{a}) \cdot \hat{a}

Where \hat{a} is the unit vector of \vec a, dimensionless and \bullet is the operator of scalar product.

The unit vector of \vec a is:

\hat{a} = \frac{\vec {a}}{\|\vec a\|}

Where \|\vec {a}\| is the norm of \vec a, whose value is determined by Pythagorean Theorem.

The component of \vec{b} parallel to \vec {a} is:

\|\vec {a}\| = \sqrt{3^{2}+(-1)^{2}+0^{2}}

\|\vec {a}\| = \sqrt{10}

\hat{a} = \frac{1}{\sqrt{10}} \cdot (3\,i-j)

\hat{a} = \frac{3}{\sqrt{10}}\,i -\frac{1}{\sqrt{10}} \,j

\vec{b}\bullet \hat{a} = (2)\cdot \left(\frac{3}{\sqrt{10}} \right)+(1)\cdot \left(-\frac{1}{\sqrt{10}} \right)+(-3)\cdot \left(0\right)

\vec b \bullet \hat{a} = \frac{5}{\sqrt{10}}

\vec b_{\parallel} = \frac{5}{\sqrt{10}}\cdot \left(\frac{3}{\sqrt{10}}\,i-\frac{1}{\sqrt{10}}\,j  \right)

\vec {b}_{\parallel} = \frac{3}{2}\,i-\frac{1}{2}\,j

Now, the component of \vec {b} perpendicular to \vec{a} is found by vector subtraction:

\vec{b}_{\perp} = \vec {b}-\vec {b}_{\parallel}

If \vec b = 2\,i+j-3\,k and \vec {b}_{\parallel} = \frac{3}{2}\,i-\frac{1}{2}\,j, then:

\vec{b}_{\perp} = (2\,i+j-3\,k)-\left(\frac{3}{2}\,i-\frac{1}{2}\,j  \right)

\vec b _{\perp} = \frac{1}{2}\,i+\frac{3}{2}\,j-3\,k

4 0
3 years ago
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Effectus [21]

Answer:

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Step-by-step explanation:

Given

10 - 2(3x + 4) < 11 ← distribute and simplify left side

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6 0
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ZanzabumX [31]

Answer:

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to find the zeros let f(x) = 0 , that is

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the factors are + 6 and - 1 , since

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(x + 6)(x - 1) = 0 ← in factored form

equate each factor to zero and solve for x

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