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Dmitry_Shevchenko [17]
3 years ago
5

When a glucose molecule loses a hydrogen atom as the result of an oxidation-reduction reaction in glycolysis, the glucose is?

Chemistry
1 answer:
maria [59]3 years ago
7 0
Reduced- in a way losing an H means gaining an e-
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Which element would you expect to be more reactive: phosphorus (P) or fluorine (F)
Studentka2010 [4]

Answer:

Fluorine

Explanation:

Fluorine is the most electronegative element because it has 5 electrons in it's 2P shell.

4 0
2 years ago
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What quantity of heat is transferred when a 150.0g block of iron metal is heated from 25.0°C to 73.3°C? What is the direction of
s344n2d4d5 [400]

The direction of heat flow is increased which means blocks temperature is higher and hotter than it was before

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2 years ago
Perform the following mathematical operation and report the answer to the correct number of significant figures? ( I have watche
professor190 [17]

0.008 ÷ 51.3 = 0.0002

Sig Figs

1

0.0002

Decimals

4

0.0002

Scientific Notation

2 × 10-4

E-Notation

2e-4

Words

zero point zero zero zero two

I HOPE I HELP

7 0
2 years ago
Iron is biologically important in the transport of oxygen by red blood cells from the lungs to the various organs of the body. I
Aneli [31]

Answer : The number of iron atoms present in each red blood cell are, 1.077\times 10^9

Explanation :

First we have to calculate the moles of iron.

\text{Moles of iron}=\frac{\text{Mass of iron}}{\text{Molar mass of iron}}=\frac{2.90g}{55.85g/mole}=0.0519moles

Now we have to calculate the number of iron atoms.

As, 1 mole of iron contains 6.022\times 10^{23} number of iron atoms

So, 0.0519 mole of iron contains 0.0519\times 6.022\times 10^{23}=3.125\times 10^{22} number of iron atoms

Now we have to calculate the number of iron atoms are present in each red blood cell.

Number of iron atoms are present in each red blood cell = \frac{\text{Number of iron atoms}}{\text{Total number of red blood cells}}

Number of iron atoms are present in each red blood cell = \frac{3.125\times 10^{22}}{2.90\times 10^{13}}

Number of iron atoms are present in each red blood cell = 1.077\times 10^9

Therefore, the number of iron atoms present in each red blood cell are, 1.077\times 10^9

6 0
2 years ago
Please help I will give brainliest.
iris [78.8K]

Answer:

the second one looks like it so I picked the second one

8 0
3 years ago
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