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Dmitry_Shevchenko [17]
3 years ago
5

When a glucose molecule loses a hydrogen atom as the result of an oxidation-reduction reaction in glycolysis, the glucose is?

Chemistry
1 answer:
maria [59]3 years ago
7 0
Reduced- in a way losing an H means gaining an e-
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The rate constant for this second‑order reaction is 0.610 M − 1 ⋅ s − 1 0.610 M−1⋅s−1 at 300 ∘ C. 300 ∘C. A ⟶ products A⟶product
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Answer: It takes 3.120 seconds for the concentration of  A to decrease from 0.860 M to 0.260 M.

Explanation:

Integrated rate law for second order kinetics is given by:

\frac{1}{a}=kt+\frac{1}{a_0}

k = rate constant = 0.610M^{-1}s^{-1}

a_0 = initial concentration = 0.860 M

a= concentration left after time t = 0.260 M

\frac{1}{0.260}=0.860\times t+\frac{1}{0.860}

t=3.120s

Thus it takes 3.120 seconds for the concentration of  A to decrease from 0.860 M to 0.260 M.

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<em>Hope this helps!</em>

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