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3 years ago

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A halogen-lighting manufacturer packs 64 halogen lamps ink a cube-shaped container. the manufacturer has been asked by his distr

ibutors to package the lamps in a smaller container that holds 8 lamps. Write the number in exponential form

1 answer:

pishuonlain [190]3 years ago

4 0

64 divided by 8 = 8

So you're answer would be 8

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Please help me out! as soon as possible!!! I will give you brainiest!

Romashka-Z-Leto [24]

Answer:

give me brainlyest

Step-by-step explanation:

0 x i took the quiz

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3 years ago

Calculus1 help involving graphs.

tatuchka [14]

Answer:

-0.67

Step-by-step explanation:

Pick two points on the tangent line, and find the slope between them.

The line passes through approximately (30,145) and (90, 105).

m = (105 − 145) / (90 − 30)

m = -0.67

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3 years ago

If the number of employed persons equals 180 million, the number of unemployed persons equals 15 million, and the number of pers

beks73 [17]

Answer:

$\text{Unemployment rate}\approx 7.7\%$

$\text{Labor force participation rate}\approx 92.9\%$

Step-by-step explanation:

We have been given that the number of employed persons equals 180 million. The number of unemployed persons equals 15 million, and the number of persons over age 16 in the population equals 210 million. We are asked to find the unemployment rate and the labor force participation rate.

$\text{Unemployment rate}=\frac{\text{Number of unemployed person}}{\text{Labor force}}\times 100\%$

We know that labor force is equal to employed population plus unemployed population.

$\text{Unemployment rate}=\frac{\text{15 million}}{\text{180 million + 15 million}}\times 100\%$

$\text{Unemployment rate}=\frac{\text{15 million}}{\text{195 million}}\times 100\%$

$\text{Unemployment rate}=0.0769230769\times 100\%$

$\text{Unemployment rate}=7.69230769\%$

$\text{Unemployment rate}\approx 7.7\%$

Therefore, the unemployment rate is approximately 7.7%.

$\text{Labor force participation rate}=\frac{\text{Labor force}}{\text{Total eligible population}}\times 100\%$

$\text{Labor force participation rate}=\frac{\text{195 million}}{\text{210 million}}\times 100\%$

$\text{Labor force participation rate}=\frac{195}{210}\times 100\%$

$\text{Labor force participation rate}=0.9285714285714286\times 100\%$

$\text{Labor force participation rate}=92.85714285714286\%$

$\text{Labor force participation rate}\approx 92.9\%$

Therefore, the labor force participation rate is approximately 92.9%.

4 0

3 years ago

Solve by using elimtation

Wewaii [24]

Answer:

1. x = 5, y = 13/2

2. x = 15 , y = 24

Step-by-step explanation:

Solve the following system:

{8 y + 6 x = 82 | (equation 1)

{6 y + 9 x = 84 | (equation 2)

Swap equation 1 with equation 2:

{9 x + 6 y = 84 | (equation 1)

{6 x + 8 y = 82 | (equation 2)

Subtract 2/3 × (equation 1) from equation 2:

{9 x + 6 y = 84 | (equation 1)

{0 x + 4 y = 26 | (equation 2)

Divide equation 1 by 3:

{3 x + 2 y = 28 | (equation 1)

{0 x + 4 y = 26 | (equation 2)

Divide equation 2 by 2:

{3 x + 2 y = 28 | (equation 1)

{0 x + 2 y = 13 | (equation 2)

Divide equation 2 by 2:

{3 x + 2 y = 28 | (equation 1)

{0 x + y = 13/2 | (equation 2)

Subtract 2 × (equation 2) from equation 1:

{3 x + 0 y = 15 | (equation 1)

{0 x + y = 13/2 | (equation 2)

Divide equation 1 by 3:

{x + 0 y = 5 | (equation 1)

{0 x + y = 13/2 | (equation 2)

Collect results:

Answer: {x = 5, y = 13/2

_____________________________________

Solve the following system:

{8 y + 3 x = 237 | (equation 1)

{3 y + 5 x = 147 | (equation 2)

Swap equation 1 with equation 2:

{5 x + 3 y = 147 | (equation 1)

{3 x + 8 y = 237 | (equation 2)

Subtract 3/5 × (equation 1) from equation 2:

{5 x + 3 y = 147 | (equation 1)

{0 x + (31 y)/5 = 744/5 | (equation 2)

Multiply equation 2 by 5/31:

{5 x + 3 y = 147 | (equation 1)

{0 x + y = 24 | (equation 2)

Subtract 3 × (equation 2) from equation 1:

{5 x + 0 y = 75 | (equation 1)

{0 x + y = 24 | (equation 2)

Divide equation 1 by 5:

{x + 0 y = 15 | (equation 1)

{0 x + y = 24 | (equation 2)

Collect results:

Answer: {x = 15 , y = 24

3 0

2 years ago

Foram prescritos 500mg de dipirona para uma criança com febre.Na unidade tem disponivel ampola de 1g/2ml.Quantos g vão ser admin

Valentin [98]

De acordo com a disponibilidade da unidade, há apenas a seguinte dosagem: 1g/2mL - ou seja, uma grama de dipirona a cada 2mL

O enunciado está meio mal formulado, pois é dito que foram prescritos 500mg de dipirona e é essa quantidade de farmaco que a criança tem que tomar. Deseja-se saber quantos mL deverao ser administrados.

Fazendo a classica regra de 3, podemos chegar no volume desejado:

(atentar que 500mg = 0,5g)

g mL

1 --------- 2

0,5 --------- X

1 . X = 0,5 . 2

<h3>X = 1mL</h3>

8 0

3 years ago