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1 year ago

Simplify the following algebraic expressions.

Mathematics

2 answers:

klio [65]1 year ago

7 0

Answer:

A) 8x - 4 || B) 6x + 29

Step-by-step explanation:

A) -2x + 5 + 10x - 9

→ -2x+10x+5-9

→ -2x+10x-4

→ 8x - 4

B) 3(x + 7) + 2(-x + 4) + 5x

→ 3x + 21 - 2x + 8 + 5x

→ 6x + 29

labwork [276]1 year ago

4 0

Answer:

A) 8x - 4

B) 6x + 29

Step-by-step explanation:

A) -2x + 5 + 10x - 9 : given

= (10x - 2x) + (5 - 9) : put like terms together

= 8x - 4 : group

B) 3(x + 7) + 2(-x + 4) + 5x : given

= 3x + 21 - 2x + 8 + 5x : expand

= (3x - 2x + 5x) + (21 + 8) : put like terms together

= 6x + 29 : group

Thanks! Have a great day studying!

Answered by : ms115

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% slope = m
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3 years ago

A box contains three plain pencils and 5 pens. A second box contains three colored pencils and three crayons. One item from each

worty [1.4K]

Answer:

Therefore the probability that a pen from the first box and a crayon from the second box are selected is $\frac5{16}$

Step-by-step explanation:

Probability:

The ratio of the number of favorable outcomes to the number all possible outcomes of the event.

$Probability=\frac{\textrm{The number favorable outcomes}}{\textrm{The number all possible}}$

Given that,

Three plain pencils and 5 pens are contained by the first box.

Total number of pens and pencils is =(3+5)=8

The probability that a pen is selected from the first box is

=P(A)

$=\frac{\textrm{The number pens}}{\textrm{Total number of pens and pencils}}$

$=\frac{5}{8}$

A second box contains three colored pencils and three crayons.

Total number of pencils and crayons is =(3+3)=6

The probability that a crayon is selected from the second box is

=P(B)

$=\frac{\textrm{The number of crayon}}{\textrm{Total number of crayons and pencils}}$

$=\frac{3}{6}$

Since both events are mutually independent.

The required probability is multiple of the events

Therefore the required probability is

$=\frac58\times \frac36$

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3 years ago

Write an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the line described by y=1/2

Morgarella [4.7K]

Answer:

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Step-by-step explanation:

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2 years ago

____ [38]

Answer:

y = 5x+3

Step-by-step explanation:

a general line is represented by the equation:

y = mx + n

a line with m=5, that goes through (-1,-2), should satisfy the equation:

-2 = 5×(-1) + n

this is because any point on the line, satisfies it's equation.

from this we get n = 3, hence our answer

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1 year ago

A quantity P is an exponential function of time I, such that P = 160 when t = 6 and P = 150 when I = 4. Use the given informatio

Klio2033 [76]

Answer:

k = 0.032
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Step-by-step explanation:

Perhaps you want to use the points (t, P) = (4, 150) and (6, 160) to find the parameters P0 and k in the equation ...

$P(t)=P_0\cdot e^{kt}$

We know from the given points that we can write the equation as ...

$P(t)=150\left(\dfrac{160}{150}\right)^{(t-4)/(6-4)}=150\left(\dfrac{16}{15}\right)^{\frac{t}{2}-2}\\\\=150\left(\dfrac{16}{15}\right)^{-2}\times\left(\left(\dfrac{16}{15}\right)^{\frac{1}{2}}\right)^t$

Comparing this to the desired form, we see that ...

$P_0=150\left(\dfrac{16}{15}\right)^{-2}\approx 131.836\\\\e^{k}=\left(\dfrac{16}{15}\right)^{1/2}\rightarrow k=\dfrac{1}{2}(\ln{16}-\ln{15})\approx 0.0322693$

So, the approximate equation for P is ...

$P(t)=131.836\cdote^{0.032t}$

And the parameters of interest are ...

k = 0.032
P0 = 131.836

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2 years ago