2 years ago

Algae and other phytoplankton are the major producers of the earth's:

Chemistry

1 answer:

vredina [299]2 years ago

4 0

Answer:

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What is the percent yield if 107.50 g NH3 reacts with excess O2 according to the

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81.59%

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First we convert 107.50 g of NH₃ into moles, using its molar mass:

107.50 g NH₃ ÷ 17 g/mol = 6.32 mol NH₃

Now we calculate how many moles of NO would have been formed by the complete reaction of 6.32 moles of NH₃:

6.32 mol NH₃ * $\frac{4molNO}{4molNH_3}$ = 6.32 mol NO

Then we convert 6.32 moles of NO to grams, using its molar mass:

6.32 mol NO * 30 g/mol = 189.60 g NO

Finally we calculate the percent yield:

154.70 g / 189.60 g * 100% = 81.59%

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