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bekas [8.4K]
2 years ago
6

Which of the following is an oxidation? Select all that apply

Chemistry
1 answer:
butalik [34]2 years ago
7 0

Answer:

2Na=Ca(OH)000.1 AgBr=2KF 2KBr=LiNO

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B. Magnesium + Hydrogen Sulfide (Reactors) ---->  Magnesium Sulfide + Hydrogen (Products)

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3 years ago
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How much energy does it take to melt 2 kg of ice? (Refer to table of<br> constants for water.)
ioda
It would be C

2 kg x 1000 g/kg x 1mol/18.02 x 6.03 kj/mol = 669kj


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3 years ago
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​29. A gas has a volume of 1.75 L at -23°C and 150.0 kPa.
arsen [322]

The answer for the following mention bellow.

  • <u><em>Therefore the final temperature of the gas is 260 k</em></u>

Explanation:

Given:

Initial pressure (P_{1}) = 150.0 kPa

Final pressure (P_{2}) = 210.0 kPa

Initial volume (V_{1}) = 1.75 L

Final volume (V_{2}) = 1.30 L

Initial temperature (T_{1}) = -23°C = 250 k

To find:

Final temperature (T_{2})

We know;

According to the ideal gas equation;

P × V = n × R ×T

where;

P represents the pressure of the gas

V represents the volume of the gas

n represents the no of moles of the gas

R represents the universal gas  constant

T represents the temperature of the gas

We know;

\frac{P*V}{T} = constant

\frac{P_{1} }{P_{2} } × \frac{V_{1} }{V_{2} } = \frac{T_{1} }{T_{2} }

Where;

(P_{1}) represents the initial pressure of the gas

(P_{2}) represents the final pressure of the gas

(V_{1}) represents the initial volume of the gas

(V_{2}) represents the final volume of the gas

(T_{1}) represents the initial temperature of the gas

(T_{2}) represents the final temperature of the gas

So;

\frac{150 * 1.75}{210 * 1.30} = \frac{260}{T_{2} }

(T_{2}) =260 k

<u><em>Therefore the final temperature of the gas is 260 k</em></u>

<u><em></em></u>

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3 years ago
Why can filtration not be used to seperate a mixture of 2 liquids ​
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Answer:

Filtration works best when the solute isn't dissolve in the solvent. For instance, sand and water can be seperated through filtration because both compounds do not dissolve with each other. However, sugar and water would not be seperated through filtration as they dissolve with each other.

-google :)

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3 years ago
Metals present in municipal wastewater may still be present in treated sewage sludge; ______
Marrrta [24]
Metals present in municipal waste water may still be present in treated sewage sludge IN CONCENTRATIONS THAT MAY AFFECT THE PUBLIC HEALTH. Sewage sludge is an end product of municipal waste water treatment and it contains many of the pollutant that are removed from the waste water. 
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