Electricity from renewable resources such as solar, geothermal, and wind generally does not contribute to climate change or local air pollution since no fuels are combusted.
The student should set up an experiment in which he will require a crucible, a sample of hydrated copper sulfate (CuSO₄ <span>• 5H</span>₂O), a hot plate and a digital mass balance.
First, the student should check the mass of the empty crucible, then add the sample to the crucible and check the mass again. The difference is the mass of the sample.
Next, the student should place the crucible on a hot plate and begin heating the sample. After regular time intervals, such as two minutes, the students should measure the mass of the crucible and sample and note it down until it stops decreasing.
After a final mass of the sample has been obtained, the student may subtract this from the initial mass and find the mass of water evaporated.
Answer:
Dear frnd, water is a conductor of electricity and short circuit means a damage in electrical component in a device. Thus,water will spread the fire.
Explanation:
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Answer is: dissolve 74,9 grams CuSO₄·5H₂O in one liter volumetric flask.
V(CuSO₄·5H₂O) = 1 L.
c(CuSO₄·5H₂O) = 0,30 mol/L.
n(CuSO₄·5H₂O) = V(CuSO₄·5H₂O) · c(CuSO₄·5H₂O) .
n(CuSO₄·5H₂O) = 1 L · 0,3 mol/L.
n(CuSO₄·5H₂O) = 0,3 mol.
m(CuSO₄·5H₂O) = n(CuSO₄·5H₂O) · M(CuSO₄·5H₂O).
m(CuSO₄·5H₂O) = 0,3 mol · 249,7 g/mol.
m(CuSO₄·5H₂O) = 74,9 g.