Answer:
547 L of water vapour
Explanation:
Equation of reaction: 2[CaSO4.2H20] + Heat ---> 2[CaSO4.½H2O] + 3H20
From the equation of reaction above, 2 moles of gypsum when heated produces 2 moles of plaster of Paris and 3 moles of water vapour.
Molar mass of gypsum = 172 g/mol
Molar mass of H2O = 18 g/mol
Therefore, 2 * 172 g of gypsum produces 3 * 18 g of water vapour
i.e. 344 g of gypsum produces 54 g of H2O
2 Kg(2000 g) of gypsum will produce (54 * 2000)/344 g of water vapour = 313.95 of water vapour.
Volume of water vapour produced = mass/density
Volume of water vapour = 313.95 g/ 0.574 g/L = 547 L of water vapour
Therefore 547 L of water vapour are produced
Answer:
By making observations and doing experiments
The answer would be the <span>Chemical formula for ammonia by
hydrogen and nitrogen gas: 1 N2 + 3 H2 --> 2 NH3 t<span>hen use stoichiometry. You know you have enough
nitrogen gas to react, so you can just straight convert mol H2 to mol NH3,
where 3 mol H2 = 2 mol NH3.
<span>3.44 mol H2 * (2 mol NH3 / 3 mol H2) = 2.29 mol NH3</span></span></span>
Eezy real talk ma frend!
The fromula for sodium cyanide is NaCn.
Answer:
you are right
Explanation:
and i do not need to explain it because you did