Answer:
A mass of 4 Kg rest on the horizontal plane. The plane is gradually inclined until at an angle of θ=15
∘
with the horizontal,the mass just being to slide what is the coffeficient of static friction between the block & the surface.
Explanation:
Answer:
The system's kinetic energy changes by 3.6 J
Explanation:
The given parameters are;
The number of cart = 2
The mass of each cart = 0.5kg
The initial length of the spring = 0.50 m
The final length of the spring =T0.3 m
The change in position of the first cart = 0.6 m
The energy given to the first cart = Work done by the force = Force × Displacement
The initial kinetic energy of the two cart moving together = Energy given to the first cart = 6.0 × 0.2 = 1.2J
The kinetic energy given to the two cart combined = The applied force × The total displacement of the two cart as they move together
The kinetic energy given to the two cart combined = 6.0 × (0.6 - 0.2)
The kinetic energy given to the two cart combined = 6.0 × 0.4 = 2.4 J
The total kinetic energy given to the two cart = 1.2 + 2.4 = 3.6 J
The total kinetic energy given to the two cart = 3.6 J
The system's kinetic energy changes by 3.6 J.
The sun is a star, not a planet. Jupiter is the biggest planet in the solar system. :)
First let us calculate for the moles of CH3OH formed:
moles CH3OH = 23 g / (32 g / mol) = 0.71875 mol
We see that there are 2 moles of H2 per mole of CH3OH, so:
moles H2 = 0.71875 mol * 2 = 1.4375 mol
Assuming ideal gas behaviour, we use the formula:
PV = nRT
V = nRT / P
V = 1.4375 mol * (62.36367 L mmHg / mol K) * (90 + 237.15
K) / 756 mm Hg
<span>V = 43.06 Liters</span>