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AveGali [126]
3 years ago
5

PICTURE BELOW PLEASE HELP ☺ (SCIENCE)

Physics
2 answers:
slamgirl [31]3 years ago
6 0
The answer to your question is, A!
Your Welcome!
Dvinal [7]3 years ago
5 0
Your answer would be A. ☻♥
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A 200 g piece of iron is heated to 100°C. It is then dropped into water to bring its temperature down to 22°C. What is the amoun
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The piece of iron is brought from a temperature of 100C to a temperature of 22C. In this process, the heat released by this piece of iron is
Q=m C_s \Delta T
where m=200 g is the mass of the piece of iron, C_s = 0.444 J/(g C) is the iron's specific heat, and the temperature variation is \Delta T = 22^{\circ}-100^{\circ}=-78^{\circ}C. Using these values, the amount of heat released by the iron is
Q=(200 g)(0.441 J/(gC))(-78C)=-6926J=-6.9 kJ
With negative sign because it is amount of heat released. This heat is then trasferred to the water, so the amount of heat absorbed by the water is Q=6.9 kJ.
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3 years ago
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What will most likely happen if a light wave moves from the air into a solid? A) It will increase in wavelength. B) It will decr
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Answer:

it will decrease speed

Explanation:

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3 years ago
Calculate the energy absorbed when 13 kg of liquid water raises from 18°C to 100°C and then boils at 100°C.
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Answer:

the energy absorbed is 4.477 x 10⁶ J

Explanation:

mass of the liquid, m = 13 kg

initial temperature of the liquid, t₁ = 18 ⁰C

final temperature of the liquid, t₂ = 100 ⁰C

specific heat capacity of water, c = 4,200 J/kg⁰C

The energy absorbed is calculated as;

H = mcΔt

H = mc(t₂ - t₁)

H = 13 x 4,200(100 - 18)

H = 4.477 x 10⁶ J

Therefore, the energy absorbed is 4.477 x 10⁶ J

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