Answer:
T = 6.0 N
Explanation:
given,
mass of the cord = 0.46 Kg
length of the supports = 7.2 m
time taken to travel = 0.74 s
tension in the chord = ?
using formula for tension calculation
![T = \dfrac{v^2.m}{l}](https://tex.z-dn.net/?f=T%20%3D%20%5Cdfrac%7Bv%5E2.m%7D%7Bl%7D)
![v = \dfrac{l}{s}](https://tex.z-dn.net/?f=v%20%3D%20%5Cdfrac%7Bl%7D%7Bs%7D)
![v = \dfrac{7.2}{0.74}](https://tex.z-dn.net/?f=v%20%3D%20%5Cdfrac%7B7.2%7D%7B0.74%7D)
v = 9.73 m/s
now, calculation of tension
![T = \dfrac{9.73^2\times 0.46}{7.2}](https://tex.z-dn.net/?f=T%20%3D%20%5Cdfrac%7B9.73%5E2%5Ctimes%200.46%7D%7B7.2%7D)
T = 6.0 N
The tension in the cord is equal to 6.0 N.
When the object is at the focal point the angular magnification is 2.94.
Angular magnification:
The ratio of the angle subtended at the eye by the image formed by an optical instrument to that subtended at the eye by the object when not viewed through the instrument.
Here we have to find the angular magnification when the object is at the focal point.
Focal length = 6.00 cm
Formula to calculate angular magnification:
Angular magnification = 25/f
= 25/ 8.5
= 2.94
Therefore the angular magnification of this thin lens is 2.94
To know more about angular magnification refer:: brainly.com/question/28325488
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Answer:
he tail of the arrow moves a distance of 0.5 m as the arrow is shot. yare yare daze
Explanation:
Scalar Quantity :-
→ These are the quantities with magnitude only . These quantities doesn't have to be mentioned with direction
eg.)=> Mass , Temprature .
Vector Quantity :-
→ These quantities are described with both Magnitude and Direction . These quantities follow special type of algebra called Vector algebra .
eg.)=> Force , Displacement
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