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erica [24]
3 years ago
6

How do very high density objects appear in an ultrasound?

Physics
1 answer:
evablogger [386]3 years ago
7 0
<span>Density is entirely unrelated to an object's size. It is a property of a given</span>
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The earth's interior heat and pressure drive a process of heat transfer in the mantle called _____.
Galina-37 [17]
Convection. It is the transfer of heat by the circulation and movement of the molecules that come from liquid or gas.
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3 years ago
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An example for curvilinear motion.
Shkiper50 [21]

Ball thrown into the air at an angle.

5 0
2 years ago
What animals were delisted in july 2019?
andrezito [222]

The animals which were delisted from the endangered species in July 2019 is Grey Wolf

Answer: Grey wolf

<u>Explanation:</u>

The ultimate goal of the Endangered Species Act was to preserve the species that are in the verge of extinction. The species are conserved and taken care of till they can be left free in the wild for it to survive of it's own.If the species has crossed all the recovery goals then they are delisted.

The grey wolf in July 2019 was delisted from the endangered species list. Now it is calculated that there are 6000 wolves that are found. But yet the grey wolf has not returned back to their livelihood and also to their sutable habitat.

5 0
3 years ago
The Hubble Space Telescope has a mass of 1.16*10^ 4 kg and orbits the Earth at an altitude of 5.68 * 10 ^ 5 above Earth's surfac
andrezito [222]

Answer:

E=8.13\times 10^{12}\ J

Explanation:

Given that,

The mass of a Hubble Space Telescope, m_1=1.16\times 10^4\ kg

It orbits the Earth at an altitude of 5.68\times 10^5\ m

We need to find the potential energy the telescope at this location. The formula for potential energy is given by :

E=\dfrac{Gm_1m_e}{r}

Where

m_e is the mass of Earth

Put all the values,

E=\dfrac{6.67\times 10^{-11}\times 1.16\times 10^4\times 5.97\times 10^{24}}{5.68\times 10^5}\\\\E=8.13\times 10^{12}\ J

So, the potential energy of the telescope is 8.13\times 10^{12}\ J.

5 0
2 years ago
Does an increase in velocity necessarily mean an increase in acceleration?
Vinil7 [7]
We know, acceleration = final velocity - initial velocity / time
Here, if velocity is increasing, then, 
Final velocity > initial velocity, in that case, acceleration is also increasing, as it is directly proportional to velocity

In short, Your Answer would be "Yes"

Hope this helps!
3 0
2 years ago
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