Answer:
Single replacement
Explanation:
A single replacement reaction is a reaction in which the less reactive elements are replaced by the more reactive element in a compound. This is so because the more reactive element are higher in the electrochemical series element than the less reactive elements
Volume of the original block (V) of length (l), width (w) and height (h) is given by the following equation

hence volume of original block, V = (6)(4)(10) = 
Now say we cut this block in two equal parts, than the length of new block will be
; where as its width and height will be same as of original block i.e. 4 cm and 10 cm respectively.
So, Volume of half-block is
; or we can say that the volume of half-block is half that of orignal block.
Answer:
Disregard a goal if you don't achieve it
Explanation:
This is because in achieving your targets/goals/dreams rewarding yourself for every small accomplishment is very important. It’ll help to keep you motivated and keep your head in the game. Similarly setting short and long-term objectives also plays a vital role. Setting a date is also important because it helps you to put your plan into action. However, disregarding a goal isn’t an option
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Answer:
a.v=u+v/2
a.v=s/t
combining two equation we get,
u+v/2=s/t
(u+v)t/2=s
(u+v)t/2=s
{u+(u+at)}t/2=s
(u+u+at)t/2=s
(2u+at)t/2=s
2ut+at^2/2=s
2ut/2+at^2/2=s
UT +1/2at^2=s
proved
a=v-u/t
at=v-u
u+at=v
The final stabilized temperature will be between 0 °C and 50 °C.
<h3>
Calorimetry:</h3>
The enthalpy of fusion of ice is 334 J/g. The specific heat of water is 4.2 J/g.
To cool 100 g of water from 100 °C to 0 °C would require the removal of
4.2 x 100 x 100 = 42000 J.
To melt the ice would require the addition of
334 x 100 = 33400 J
∴ 42000 > 33400 thus you can melt all the ice and have some heat to spare, specifically 42000 - 33400 = 8600 J
Now use this to warm up 100+100 = 200 g of water at 0 °C
The final stabilized temperature;
8600 / (200 x 4.2) = 10.23 °C
Therefore, the final stabilized temperature is 10.23 °C
Learn more about Calorimetry here:
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