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MAXImum [283]
3 years ago
6

A spacecraft is launched from Earth toward the moon.

Physics
2 answers:
elena55 [62]3 years ago
6 0

Answer:

closer to the moon

Explanation:

got it right on time 4 learning

Leona [35]3 years ago
5 0
Closer to the moon than to Earth because Earth has a greater mass than the moon
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A 4kg object has a momentum of 12 kg*m/s, what is the objects velocity?
Bezzdna [24]
Momentum = mass x velocity
12 = 4 x v | ÷ both sides by 4
12 ÷ 4 =v
v= 3 m/s
8 0
3 years ago
In a particular region, there is a uniform magnetic field with a magnitude of 2.00 T. You take a particle with a charge of +6.00
expeople1 [14]

Answer:

a) 1.68 N b) 0 c) 14.5º

Explanation:

a)

  • The force on a charge moving in a magnetic field, is a vector perpendicular to the plane defined by the velocity of the charge and the magnetic field.
  • The magnitude of the force F is given by the following expression:

       F = q*v*B*sin\theta (1)

  • where q= magnitude of the charge of the particle, v=velocity of the particle, B= magnitude of the magnetic field, and θ= angle between v and B.
  • Replacing by the known values in (1) we have:

       F = q*v*B*sin\theta (1) = 6.00e-6C*1.40e5m/s*2T*sin\theta=\\ \\ F= 1.68N*sin\theta

  • The maximum possible value of F happens when sin θ =1
  • This means that v and B are perpendicular each other (in the same plane)
  • So, Fmax = 1.68 N

b)

  • If the maximum possible value of F happens when sin θ = 1, the minimum possible is when sin θ = 0.
  • In this case, when v  and B are parallel each other, the force is just 0.

c)

  • If the force is 0.25 of the maximum possible, (which is when sin θ =1), this means that sin θ = 0.25, as it can be seen below:

       F_{\theta} = q*v*B*sin \theta = 0.25*Fmax\\ F_{\theta} = q*v*B*sin\theta= 0.25 (q*v*B*sin 90) \\ sin \theta = 0.25

       \theta = sin^{-1} (0.25) =14.5 deg

  • The angle between the velocity v and the magnetic field B is 14.5º.
3 0
4 years ago
The wavelength is 1. 87 x 10-7 m. What is the frequency?.
jeka57 [31]

Answer:

11.7 im pretty sure. i did the work so it should be correct

3 0
2 years ago
For incompressible fluids, density changes
mr_godi [17]
Just to make it easier on you It’s C.Pressure
7 0
3 years ago
Lindsay is planning a flight from St. Catherines to Hamilton, which lies due west of St. Catharines.
Schach [20]

Lindsay should fly the plane in the direction [W 12.5° S] to get Hamilton.

Using Sine rule to solve this question

Sine rule => SinA/a = SinB/b = SinC/c = constant

The magnitude of wind is 50 with an angle of 60 degrees.

The magnitude of plane is 200 and the angle at which it should fly is unknown and should be θ.

One side is 50 km/hr at an angle of 60 degrees.

sin 60°/200 = sin θ / 50

50 × sin 60° = 200 × sin θ

√3/2 = 4 × sin θ

√3/8 = sin θ

sin θ = 0.2165

θ = sin⁻¹(0.2165)

θ = 12.5°

So Lindsay have to fly the plane in the direction of [W 12.5° S].

Learn more about Sine Rule here:

brainly.com/question/27174058

#SPJ10

3 0
2 years ago
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