Answer:
g(q) = 5/8q
Step-by-step explanation:
-7q + 12r = 3q - 4r
Add 4r to each side
-7q + 12r+4r = 3q - 4r+4r
-7q +16r = 3q
Add 7q to each side
-7q+7q +16r = 3q+7q
16r = 10q
Divide each side by 16
16r/16 = 10q/16
r = 5q/8
g(q) = 5/8q
If you have an average of 97.2 on your current exam and you get a 99 on your next exam, your average will increase.
- Mean in mathematics is the sum (total) of all the values in a set of data, such as numbers or measurements, divided by the total number of values.
- To find the average, sum all the values in the set. Then divide the total by the number of values.
We have the current examination mean, xold = 97.2
Now, we receive, x = 99 on the next examination, the new mean will be:
xnew = (xold + x)/N
xnew = (97.2+99)/2
xnew = 196.2/2
xnew = 98.1
The new average is 98.1
98.1 > 97.2
So if you score 99 on your next exam, your average will increase.
Learn more about mean here
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Answer:
If you know the radius of a circular track, you can use physics to calculate how fast an object needs to move in order to stay in contact with the track without falling when it reaches the top of the loop.
Answer:
yes, Abdul should expect to come up tails.
<h3>
Answer: 1</h3>
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Explanation:
We're given the height in relation to base BC, so we need to find the length of this base. This is the same as finding the distance from B to C.
Turn to the distance formula

Coincidentally, the base and height are the same. This won't always be the case.
Now we can find the area of the triangle

The area of the triangle is 1 square unit.
See diagram below.