Answer:
see below
Step-by-step explanation:
<h3>Proposition:</h3>
Let the diagonals AC and BD of the Parallelogram ABCD intercept at E. It is required to prove AE=CE and DE=BE
<h3>Proof:</h3>
1)The lines AD and BC are parallel and AC their transversal therefore,
![\displaystyle \angle DAC = \angle ACB \\ \ \qquad [\text{ alternate angles theorem}]](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%20%5Cangle%20DAC%20%3D%20%20%5Cangle%20ACB%20%5C%5C%20%20%5C%20%5Cqquad%20%5B%5Ctext%7B%20alternate%20angles%20theorem%7D%5D)
2)The lines AB and DC are parallel and BD their transversal therefore,
![\displaystyle \angle BD C= \angle ABD \\ \ \qquad [\text{ alternate angles theorem}]](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%20%5Cangle%20BD%20C%3D%20%20%5Cangle%20ABD%20%5C%5C%20%20%5C%20%5Cqquad%20%5B%5Ctext%7B%20alternate%20angles%20theorem%7D%5D)
3)now in triangle ∆AEB and ∆CED
therefore,

hence,
Proven
Answer:
-68 is not a term in the given sequence
Step-by-step explanation:
The given sequence is -12, -17, -22, -27...
There is a common difference of d=-17--12=-5
The explicit rule for this sequence is 
Or 
To find the term that has a value of -68 we equate the explicit formula and solve for n.




The position should be a natural number.
Since n is a decimal, it tells us that -68 is not a term in the given sequence
Can someone plz make a histogram for the numbers 60,60,65,71,72,75,80,88,92,95,100,152
gogolik [260]
Answer:
lol sorry i don't know. but i would try my best to find your answer
Let b be the speed of the boat, and c be the speed of the current. Then:
20/b+c=2/3 hr
20/b-c=1 hr
2/3b+2/3c=20
b-c=20
Then:
b+c=30
b-c=20
2b=50
b=25 mph
c=5 mph
☺☺☺☺
Answer:
1 )94.234
2)0.6
this is correct answer i calculate it