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kondor19780726 [428]
3 years ago
13

According to collision theory which species must collide for a chemical reaction to proceed

Chemistry
1 answer:
bogdanovich [222]3 years ago
7 0
The  Reactant species.

<span>According to collision theory ,  REACTANTS must collide for a chemical reaction to proceed.
When the different reactants species collide with one one another, the chemical bonds of the reactant molecules are broken. Then, new bonds are formed amongst the different reactant molecules to form the products.</span>
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To solve this kinematics formula use the following equation:

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Vf = 29.43 m/s and or about 29.4 m/s of reported to 3 significant figures.
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Most important groups on the periodic table?
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Imagine that a single cell below goes through four cell divisions. How many cells are produced? To find out, draw the parent cel
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16 cells are produced from a single parent cell after the fourth division of the cell.

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2 years ago
In the following chemical reaction between H_2 and Cl_2 to produce HCl, what is the mass of HCl produced and leftover reactants
ira [324]

<u>Answer:</u> The total amount of leftover reactants and HCl is 12.79 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For hydrogen gas:</u>

Given mass of hydrogen gas = 0.36 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1, we get:

\text{Moles of hydrogen gas}=\frac{0.36g}{2g/mol}=0.18mol

  • <u>For chlorine gas:</u>

Given mass of chlorine gas = 12.41 g

Molar mass of chlorine gas = 71 g/mol

Putting values in equation 1, we get:

\text{Moles of chlorine gas}=\frac{12.41g}{71g/mol}=0.175mol

The chemical equation for the reaction of hydrogen gas and chlorine gas is:

H_2+Cl_2\rightarrow 2HCl

By Stoichiometry of the reaction:

1 moles of chlorine gas reacts with 1 mole of hydrogen gas

So, 0.175 moles of chlorine gas will react with = \frac{1}{1}\times 0.175=0.175mol of hydrogen gas

As, given amount of hydrogen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, chlorine gas is considered as a limiting reagent because it limits the formation of product.

Moles of excess reactant left (hydrogen gas) = [0.18 - 0.175] = 0.005 moles

By Stoichiometry of the reaction

1 moles of chlorine gas produces 2 moles of HCl

So, 0.175 moles of chlorine gas will produce = \frac{2}{1}\times 0.175=0.350 moles of HCl

Now, calculating the mass of hydrogen gas left and HCl from equation 1, we get:

  • <u>For hydrogen gas:</u>

Molar mass of hydrogen gas = 2 g/mol

Moles of excess hydrogen gas = 0.005 moles

Putting values in equation 1, we get:

0.005mol=\frac{\text{Mass of excess hydrogen gas}}{2g/mol}\\\\\text{Mass of excess hydrogen gas}=(0.005mol\times 2g/mol)=0.01g

  • <u>For HCl:</u>

Molar mass of HCl = 36.5 g/mol

Moles of HCl = 0.350 moles

Putting values in equation 1, we get:

0.350mol=\frac{\text{Mass of HCl}}{36.5g/mol}\\\\\text{Mass of HCl}=(0.350mol\times 36.5g/mol)=12.78g

Total mass of HCl and leftover reactants = [12.78 + 0.01] = 12.79 g

Hence, the total amount of leftover reactants and HCl is 12.79 grams

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