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nikitadnepr [17]
4 years ago
13

A sample of 0.281 gg of an unknown monoprotic acid was dissolved in 25.0 mLmL of water and titrated with 0.0950 M NaOH NaOH. The

acid required 30.0 mLmL of base to reach the equivalence point.What is the molar mass of the acid?
Chemistry
1 answer:
tensa zangetsu [6.8K]4 years ago
5 0

Answer:

98.6 g/mol.

Explanation:

Equation of the reaction

HX + NaOH--> NaX + H2O

Number of moles = molar concentration × volume

= 0.095 × 0.03

= 0.00285 moles

By stoichiometry, 1 mole of HX reacted with 1 mole of NaOH. Therefore, number of moles of HX = 0.00285 moles.

Molar mass = mass ÷ number of moles

= 0.281 ÷ 0.00285

= 98.6 g/mol.

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How many molecules are in 3.10*10^-3 g of C6H12O6
joja [24]
Molas mass C6H12O6 = 180.15 g/mol

1 mole C6H12O6 -------------- 180.15 g
?? molesC6H12O6 ------------ 3.10x10⁻³ g

3.10x10⁻³ x 1 / 180.15 => 0.00001720 moles

1 mole ------------------------- 6.02x10²³ molecules
0.00001720 moles ---------- ??

0.00001720 x (6.02x10²³) / 1 => 1.035x10¹⁹ molecules
6 0
3 years ago
Write a balanced formation equation at standard conditions for the compound HCN.
Aloiza [94]
The formation of hydrogen cyanide, HCN is formed by reacting hydrogen gas, carbon and nitrogen gas, expressed in the following expression below:

<span>½ H2 (g) + C (s) + ½ N2 (g) → HCN (g) ΔHof = 135 kJ
</span>
At standard conditions, hydrogen and nitrogen exist as gases while carbon is solid. This is also an endothermic reaction due to the positive <span>ΔHof</span>
7 0
3 years ago
Read 2 more answers
An electron in an atom is known to be in a state with magnetic quantum number ml=0. What is the smallest possible value of the p
rusak2 [61]

Answer:

1

Explanation:

The principal quantum number, n, showsthe principal electron shell. which can inturn be describe as the most probable distance of the electrons from the nucleus, the larger the number n is, the farther the electron is from the nucleus, the larger the size of the orbital, and the larger the atom is. n can be any positive integer starting at 1, as n=1 designates the first principal shell (the innermost shell). When an electron is in an excited state or it gains energy, it may jump to the second principle shell, where n=2

As the energy of the electron increases, so does the principal quantum number, e.g., n = 3 indicates the third principal shell, n = 4 indicates the fourth principal shell, and so on. n=1,2,3,4…

On the other hand, the magnetic quantum number ml determines the number of orbitals and their orientation within a subshell. Consequently, its value depends on the orbital angular momentum quantum number l. Given a certain l, ml is an interval ranging from –l to +l, so it can be zero, a negative integer, or a positive integer. ml=−l,(−l+1),(−l+2),…,−2,−1,0,1,2,…(l–1),(l–2),+l

note also that: The orbital angular momentum quantum number l determines the shape of an orbital, and therefore the angular distribution. The number of angular nodes is equal to the value of the angular momentum quantum number l. Each value of l indicates a specific s, p, d, f subshell (each unique in shape.) The value of l is dependent on the principal quantum number n. Unlike n, the value of l can be zero. It can also be a positive integer, but it cannot be larger than one less than the principal quantum number (n-1): l=0,1,2,3,4…,(n−1).

So the answer is 1

3 0
3 years ago
The three naturally occurring isotopes of potassium are 39K, 38.963707u; 40K, 39.963999u; and 41K.The percent natural abundances
sweet-ann [11.9K]

Answer:

The isotopic mass of 41K is 40.9574 amu

Explanation:

Step 1: Data given

The isotopes are:  

39K with an isotopic mass of 38.963707u and natural abundance of 93.2581%

40K with an isotopic mass of 39.963999u

41K wit natural abundance of 6.7302 %

Average atomic mass =39.098 amu  

Step 2: Calculate natural abundance of 40 K

100 % - 93.2581 % - 6.7302 %

100 % = 0.0117 %

Step 3: Calculate isotopic mass of 41K

39.098 = 38.963707 * 0.932581 + 39.963999 * 0.000117 + X * 0.067302

39.098 = 36.33681 + 0.0046758 +  X * 2.067302

X = 40.9574 amu

The isotopic mass of 41K is 40.9574 amu

8 0
4 years ago
What is a non example of sustainability
DaniilM [7]
<span>oil,natural gas,coal, metals and minerals</span>
4 0
4 years ago
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