<span>The answer is 2.519 × 10^4. Use the distributive property: a × x + b × x = (a + b) × x. If a = 4.659, b = 2.14, and x = 10^4, then 4.659 × 10^4 − 2.14 × 10^4 = (4.659 - 2.14) × 10^4. Now, subtract numbers in parenthesis: 4.659 × 10^4 − 2.14 × 10^4 = (4.659 - 2.14) × 10^4 = 2.519 × 10^4.Hope this helps. Let me know if you need additional help!</span>
Answer:
Ca (s) + 2H₂O (l) → Ca(OH)₂ (aq) + H₂ (g)
Explanation:
When solid calcium reacts with water, it produces the correspondent hydroxid and hydrogen gas.
The hydroxid which is produced, is the calcium hydroxid which is a strong base, that's why you talk about a highly alkaline solution.
Ca (s) + 2H₂O (l) → Ca(OH)₂ (aq) + H₂ (g)
Calcium hydroxide is a strong base, that dissociates in water, as this:
Ca(OH)₂ → Ca²⁺ (aq) + 2OH⁻ (aq)
It's a basic solution, is providing hydroxyl ions to the medium
Carbon dioxide and Oxygen are the two gases of air which dissolves in water by diffusion The oxygen is dissolved in water so that fishes can take in oxygen through water to breathe, this is the biological importance of this process in nature. ... Fizzy drinks contain carbon dioxide dissolved in water.
Answer: Now it is proved that the atom consists of particles like electrons, protons, and neutrons.
Explanation: because he did not have the tech we do to understand atoms
Step 1
Molarity is defined as Moles of solute (NH3) divided by the volume of the solution in L
Molarity (mol/L or M) = moles of NH3/volume of the solution (L) (1)
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Step 2
The moles of solute (NH3):
0.500 % by mass means:
0.500 g/100 g solution
Moles of NH3 are calculated as:
Mass of NH3/molar mass NH3 = 0.500 g/17.0 g/mol = 0.029 moles NH3
(molar mass NH3 = 17.0 g/mol)
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Step 2
The volume of solution:
Volume is calculated from density
Density = mass solution/volume of solution
Volume = mass of solution/density = 100 g solution/0.996 g/mL => Volume = 100.4 mL
1L = 1000 mL => V = 100.4 mL = 0.1004 L
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Step 4
From (1)
Molarity = moles of NH3/volume of the solution (L) = 0.029 moles NH3/0.1004 L = 0.289 mol/L
Answer: M = 0.289 M or mol/L
