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3 years ago

What is Cot(x) / cos(x) ?

Mathematics

1 answer:

lutik1710 [3]3 years ago

8 0

Answer:

cosecx

Step-by-step explanation:

$\frac{cotx}{cosx} \\ = \frac{1}{tanx} \div cosx \\ = (1 \div \frac{sinx}{cosx} ) \div cosx \\ = \frac{cosx}{sinx} \times \frac{1}{cosx} \\ = \frac{1}{sinx} \\ = cosecx$

Note that:

$tanx = \frac{sinx}{cosx}$

$cotx = \frac{1}{tanx} = \frac{cosx}{sinx}$

$cosecx = \frac{1}{sinx}$

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Eight percent of all college graduates hired by companies stay with the same company for more than five years. The probability,

Maurinko [17]

Answer:

0.1662 = 16.62% probability that exactly 2 will stay with the same company for more than five years

Step-by-step explanation:

For each graduate, there are only two possible outcomes. Either they stay for the same company for more than five years, or they do not. Graduates are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Eight percent of all college graduates hired by companies stay with the same company for more than five years.

This means that $p = 0.08$

Sample of 11 college graduates:

This means that $n = 11$

The probability, rounded to four decimal places, that in a random sample of 11 such college graduates hired recently by companies, exactly 2 will stay with the same company for more than five years is: the absolute tolerance is +-0.0001

The tolerance means that the answer is rounded to four decimal places.

The probability is P(X = 2). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{11,2}.(0.08)^{2}.(0.92)^{11} = 0.1662$

0.1662 = 16.62% probability that exactly 2 will stay with the same company for more than five years

4 0

3 years ago

Estimate the product. Round the first factor to the nearest whole number, round the second factor to the nearest hundred, and th

castortr0y [4]

Answer:

The product is approximately 5400.

Step-by-step explanation:

9 1/16 rounded to the nearest whole number is 9.

645 3/5 rounded to the nearest hundred is 600.

Multiplying these values gives a product of 9·600 = 5400.

The product is approximately 5400.

3 0

2 years ago

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Could someone help me on question 1 thx

Ghella [55]

The answer is A!!! Hope that helped :)

4 0

2 years ago

What is the exact distance from (8, 5) to (−1, 3)? (Round to the nearest tenth)

alexira [117]

Answer:

About 9.2 units

Step-by-step explanation:

[8-(-1)^2]+[(5-3)^2]

81+4

sqrt(85)

9.2

Brainliest appreciated :)

4 0

2 years ago

Read 2 more answers

Expand (2+x)^-3 ....

pentagon [3]

Answer:

1/(x^3 + 6x^2 + 12x + 8)

Step-by-step explanation:

The first thing we do is rationalize this expression. (2+x)^-3 is written as

1/(2+x)^3

Then from there we can foil out the denominator. It is easiest to foil (2+x)(2+x) first and then multiply that product by (2+x).

(2+x)(2+x) = 4 + 4x + x^2

(4+4x+x^2)(2+x) = 8+8x+2x^2+4x+4x^2+x^3.

Then we combine like terms and put them in order to get:

x^3 + 6x^2 + 12x + 8

And of course we can't forget that this was raised to the negative third power, so our answer is 1/(x^3 + 6x^2 + 12x + 8)

6 0

2 years ago

Read 2 more answers