Mammal? Is this for science or?
It can result in decreased immunity, digestive problems, fertility problems, lower mental alertness, slowed growth. Amino acids play many different roles in the body and the symptoms vary.
Answer:
In order to find average speed during each interval, we need to divide the distance during those intervals with the period of time. So, for the first interval (day 0 to day 2) hawksbill started from 0 and reached 10 kilometers by the end of the second day. That means that it crossed 10 kilometers in 2 days, so the average speed is 10/2 which is 5 km/day. Similarly, we can calculate speed for other intervals:
• day 2 - day 3: it went from 10 to 12 km in one day, which means it crossed 2 km in one day, so the average speed is 2/1 = 2 km/day
• day 3 - day 4: at the end of the third day it reached 12 km and at the end of the day 4 it remained at 12 km. That means the hawksbill wasn't moving in that interval so the speed was 0
• day 4 - day 5: it went from 12 km to 18 km, which means it crossed 18-12=6 km in one day, so the average speed is 6/1=6 km/day
• day 5 - day 6: it went from 18 to 24 km, which means it crossed 24-18=6 km in one day, so the speed was 6/1=6 km/day
So, to summarize, during the first interval turtle was moving with average speed of 5 km/day, then 2 km/day, in the third interval it wasn't moving and in the last two intervals, it moved in average speed of 6 km/day.
Given: The population density of frogs in a portion of a pond is 12 frogs per square meter. The size of the entire pond is 370 square meters.
To find: The total population size of the frogs in the pond.
Method: Using unitary method of proportions
Solution:
Let p be the density of the frogs present per square meter.
Let A denote the total area of the pond.
∴ p = 12 frogs/m² and A = 370 m²
The total number of frogs in the pond is given by,
Therefore, there are 4440 frogs in the pond.
