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taurus [48]
4 years ago
13

Im honestly too lazy to do this so can someone pls help??? tyy!!

Physics
1 answer:
Step2247 [10]4 years ago
6 0

Answer:

I think the way to sure the building falls safely is by the engineers using too much force with a wrecking ball.

I have been busy so I hope this helps:) ily!!!! <333

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Suppose a plot of 1/λ vs f has a slope of 0.728, what is the wave velocity? Give only the numerical answer with 4 decimal place
Charra [1.4K]

Answer:

The wave velocity is 1.3736

Explanation:

A plot of inverse of wavelength (λ) versus frequency (f), can be analyzed as follows;

The vertical axis will be 1/λ and the horizontal axis will be f

slope = (Δ1/λ)/(Δf)

        = 1/(fλ)

∴ 1/(fλ) = 0.728

From wave equation, V = fλ

where;

V is the wave velocity

f is the frequency of the wave

λ is the wavelength

1/(fλ) = 0.728

1/(V) = 0.728

V = (0.728)⁻¹

V = 1.3736

Therefore, the wave velocity is 1.3736

3 0
3 years ago
Read 2 more answers
A crate is pulled with a force of 165 N at an angle 30 ° northwest. What is the resultant horizontal force on the crate?
Ad libitum [116K]

Answer:

Resultant horizontal force = 143 N

Explanation:

Since the a gle is 30° northwest, then it means the resultant force will be horizontal and as such;

Resultant horizontal force = 165 * cos 30

Resultant horizontal force = 142.89

Approximating to a whole number gives;

Resultant horizontal force = 143 N

5 0
2 years ago
Remember to identify all your data, write the equation, and show your work.
Paraphin [41]

Answer:

I believe it's 8.09 seconds, but I'm rusty on my physics.

Explanation:

The equation for solving the time it takes for an object to fall is \sqrt{2d/g}

So multiply the distance times 2, and you get 642 meters. Then you divide by gravities acceleration constant, 9.8, and you get 65.51. Finally, \sqrt{65.51}, and you get 8.09 seconds.

I pulled the equation off of wikipedia and I'm unsure if it's the correct one, so hopefully this is correct. :/

6 0
3 years ago
Which is a standard unit of measurement​
ruslelena [56]
There are some more like Time - second (s)
Amount of substance - mole (mole)
Electric current - ampere (A)
Temperature - kelvin (K)
Luminous intensity - candela (cd)

6 0
3 years ago
If the torque required to loosen a nut that holds a wheel on a car has a magnitude of 55 n·m, what force must be exerted at the
erastova [34]

Either 175 N or 157 N depending upon how the value of 48° was measured from.    
You didn't mention if the angle of 48° is from the lug wrench itself, or if it's from the normal to the lug wrench. So I'll solve for both cases and you'll need to select the desired answer.    
Since we need a torque of 55 N·m to loosen the nut and our lug wrench is 0.47 m long, that means that we need 55 N·m / 0.47 m = 117 N of usefully applied force in order to loosen the nut. This figure will be used for both possible angles.    
Ideally, the force will have a 0° degree difference from the normal and 100% of the force will be usefully applied. Any value greater than 0° will have the exerted force reduced by the cosine of the angle from the normal. Hence the term "cosine loss".     
If the angle of 48° is from the normal to the lug wrench, the usefully applied power will be:  
U = F*cos(48)  
where  
U = Useful force  
F = Force applied    
So solving for F and calculating gives:  
U = F*cos(48)  
U/cos(48) = F  
117 N/0.669130606 = F  
174.8537563 N = F    
So 175 Newtons of force is required in this situation.    
If the 48° is from the lug wrench itself, that means that the force is 90° - 48° = 42° from the normal. So doing the calculation again (this time from where we started plugging in values) we get  
U/cos(42) = F  
117/0.743144825 = F  
157.4390294 = F    
Or 157 Newtons is required for this case.
6 0
3 years ago
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