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trapecia [35]
3 years ago
5

To boil water it requires heat , what happens to the heat when the water cools down as energy can neither be destroyed nor be cr

eated ?​
Physics
2 answers:
skelet666 [1.2K]3 years ago
4 0

Answer:

Explanation:

The water particles just flow through each other. They cannot be destroyed nor created.

Dahasolnce [82]3 years ago
4 0

Answer:

The water cooling down is due to evaporation, the heat is simply changing the state of matter of the water. Energy is being used to change it's state. Evaporation causes the cooling down of something. Think of sweat?

Explanation:

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A person strikes a ball with a bat. The temperature of the ball increases by 0.06ᵒC. What accounts for the increase?
marusya05 [52]

The increase in the average kinetic energy of the ball causes the increase in the temperature of the ball.

Kinetic energy of a particle is directly proportional to its temperature.

A ball initially at rest acquires kinetic energy when an external force is applied to it. As the person strikes the ball with a bat, the ball gains momentum which increases its kinetic energy of the ball.

Temperature on the other hand, is the measure of the average kinetic energy of a particle. Consequently, as the kinetic energy of the ball increases, the temperature of the ball increases as well.

Thus, we can conclude that the increase in the average kinetic energy of the ball causes the increase in the temperature of the ball.

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2 years ago
"the toy car is about 3 inches long"is an example of a ________ observation
koban [17]

It's a quantitative observation because it includes numerical data.

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You have a series circuit powered by a 9V battery. If you double the amount of
ss7ja [257]
It gets 2 times weaker
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2 years ago
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Study the velocity vs. time graph shown.
laiz [17]

For velocity vs Time graphs, the displacement of the object from 2 seconds to 6 seconds is 30 m.

<h3>What is displacement?</h3>

The displacement is the shortest distance travelled by the particle. It is the vector quantity which re[presents both the magnitude and direction.

In velocity time graphs, the displacement is the area under the curve of the graph on the x axis.

'

A line starts at (0, 2) and ends at (6, 8) in v-t graph

Displacement is equal to the area of a triangle and a rectangle formed under the line.

Area = 1/2 base x height + length x breadth

Area = 1/2 x 6x 6 + 6x2

Area = 18 +12

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Thus, the displacement is 30 m.

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6 0
2 years ago
Two parallel plate capacitors 1 and 2 are identical except that capacitor 1 has charge +q on one plate and charge −q on the othe
Grace [21]

Answer:

a) the capacitance is the same for both capacitors.

b) The potential difference between the plates for the capacitor with charge +2q, is double of the one for the capacitor  with charge +q.

c) The electric field magnitude between the plates for the capacitor with charge +2q, is double of the one for the capacitor with charge +q

d) The energy stored between the plates for the capacitor with charge +2q, is 4 times the value for the one with charge +q  

Explanation:

a) The capacitance of a capacitor, by definition, is as follows:

C = \frac{q}{V}

Appying Gauss' Law to one of plates, it can be showed, that the capacitance (for a parallel plates capacitor) can be  expressed as follows:

C = ε*A / d

As it can be seen, it does not depend on the charge. so we conclude that the capacitance must be the same for both capacitors, due to they are identical except for the value of the charge on the plates.

b) By definition, as we said above, the capacitance is equal to the proportion between the charge of one of the plates, and the potential difference between them.

If this proportion must remain the same, and one of the capacitors has the double of  the charge than the other, the potential difference must be the double also.

c) Applying Gauss' law, to the surface of one of  the plates, and assuming a constant surface charge density σ, it can be  showed that the  electric field can be calculated as follows:

E*A = Q/ε₀ as σ=Q/A

⇒ E = σ/ε₀

As σ is directly proportional to the charge (being the area A the same), we conclude that the electric field for the capacitor with charge +2q must be the double than the one for the capacitior with charge +q.

c) The electric potential energy, stored between plates of a capacitor, can be written as follows:

Ue = \frac{1}{2} *\frac{q^{2}}{C}

If the capacitance remains the same, we can conclude that the electric potential energy for the capacitor with charge +2q, as the charge is raised to the 2nd power, must be 4 times the one for the capacitor with charge +q.

4 0
3 years ago
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