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trapecia [35]
3 years ago
5

To boil water it requires heat , what happens to the heat when the water cools down as energy can neither be destroyed nor be cr

eated ?​
Physics
2 answers:
skelet666 [1.2K]3 years ago
4 0

Answer:

Explanation:

The water particles just flow through each other. They cannot be destroyed nor created.

Dahasolnce [82]3 years ago
4 0

Answer:

The water cooling down is due to evaporation, the heat is simply changing the state of matter of the water. Energy is being used to change it's state. Evaporation causes the cooling down of something. Think of sweat?

Explanation:

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Consider 2 steel rods, A and B, B has three times the area and twice the length of A, so young modulus of B will be what factor
AVprozaik [17]

Answer:

  \frac{Y}{Y_o} = 2/3

Explanation:

The yuong modulus of a rod is defined as the relationship between the tensile strength and the strain

         Y =  \frac{ \frac{F}{A} }{\frac{\Delta L}{L_o} }

let's use the subscript "o" for rod A

         I = \frac{ \frac{F}{A_o} }{ \frac{\Delta L}{L_o} }

tells us that rod B has

         A = 3 A₀

         L = 2 L₀

we substitute

         Y = \frac{ \frac{F}{A} }{ \frac{\Delta L}{L} }

          Y = \frac{ \frac{F}{3A_o} }{ \frac{\Delta L}{ 2L_o}  }

         y = ⅔  \frac{ \frac{F}{A_o}}{ \frac{\Delta }{L_o} }

substituting the value of Y₀

          Y = ⅔  Y₀

           \frac{Y}{Y_o} = 2/3

5 0
3 years ago
Compare and contrast infrasonic and ultrasonic vibrations
Olegator [25]

Answer:

Explanation:

Ultrasonic waves are acoustic waves that are so high in frequency that humans can't hear them; however, infrasonic waves are sound waves that are lower in frequency than what humans can hear. A subsonic wave is a wave that is traveling slower than the speed of sound and a supersonic waves travels faster

8 0
3 years ago
Problem 3) Bob stands at the edge of the swimming pool holding a laser 1.5m above the ground. He shines the red laser beam onto
Vadim26 [7]

Answer:

d = 5.75m

Explanation:

Using snell's law, we have,

n₁ × sin(i) = n₂ × 2 × sin(r)

n1= refractive index of 1st medium= 1

n2=  refractive index of 2nd medium = 1.33

r= angle of reflection

therefore,

r = \sin^{-1}\frac{n_1\sin i}{n_2}

Here,

i = 90 - θ

\theta = \tan^-^1(\frac{1.5}{3} )\\\\=26.56^\circ

r = \sin^{-1}\frac{n_1\sin i}{n_2}

r = \sin^{-1}\frac{(1)\sin (90-26.56)}{1.33}\\\\r = 42.26m

\tan r = \frac{2.5}{d_1}

d_1 = \frac{2.5}{\tan (42.26)} \\\\d_1 = 2.75m

Therefore, the distance is

d = 3 + d₁

d = 3 + 2.75

d = 5.75m

6 0
3 years ago
If there is a 25 [lbs] of force acting on a 5 [lbs] of mass, what is the acceleration of that mass?
mihalych1998 [28]

Answer:

f = 25 lbs

m = 5 lbs

a =?

f = ma

25 = 5 a( divide both sides by 5)

a = 5(lbs)

5 0
2 years ago
One scientist suggests that out of the different possible locations, they should design the model and build it at the equator re
Anika [276]

Answer:

B.

I think.

Explanation:

Mars doesn't have that much of an atmosphere!

Have a great day!

7 0
2 years ago
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