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liraira [26]
3 years ago
6

Sketch the titration curve for the titration of a generic weak base B with a strong acid. The titration reaction is

Chemistry
1 answer:
Klio2033 [76]3 years ago
7 0

Answer:

Kindly check the attached picture.

Explanation:

Titration is one of the useful concept or practical in chemistry which is used in the determination of the concentration of a particular chemical specie. Without mincing words, let us dive straight into the solution to the question;

(a) Determining the equivalence point using the graph.

=> The equivalence point is the point at which there has been been "enough" addition of the acid to the base to give us the congugate acid. In the diagram showing the curve, it is the point labelled (a).

(b)The next thing is to determine the region with maximum buffering.

=> The position with the maximum buffering ranges from the point labelled (b) in the graph and it is the point when the acid and the base has been added. But the point with the maximum buffering is labeled as point (c).

(c). Determination of the point where pH = pKb.

=> The Point in which the pH = pKb is the point a

(d). The region where pH depends only on [B].

=> The starting point in the point in which the pH is dependent on the concentration of the base, [B].

(e). The region where pH depends only on [BH+].

=> This is the same point with point labelled as (a). Thus, point (a) and (e) are the same.

(f). The region where pH depends only on the amount of excess strong acid is the point labelled as (f) which is known as the post equivalence point.

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AlekseyPX

Answer:

the answer is convection

convection

6 0
3 years ago
Find ∆G for a cell whose potential is +0.24 V with 4 moles of electrons exchanged.
Setler [38]
We need to use the following formula
ΔG= -nF E_{cell}

E_{cell}= 0.24V
n= 4 moles
F= constant= 96500C/mol

let's plug in the values.

ΔG= -(4)(96500)(0.24)= -92640 J or -92.6 kJ
6 0
3 years ago
Read 2 more answers
What is the molar mass of 37.96 g of gas exerting a pressure of 3.29 on the walls of a 4.60 L container at 375 K?
Phantasy [73]

The molar mass of the gas is 77.20 gm/mole.

Explanation:

The data given is:

P = 3.29 atm,   V= 4.60 L   T= 375 K  mass of the gas = 37.96 grams

Using the ideal Gas Law will give the number of moles of the gas. The formula is

PV= nRT    (where R = Universal Gas Constant 0.08206 L.atm/ K mole

Also number of moles is not given so applying the formula

n= mass ÷ molar mass of one mole of the gas.

n = m ÷ x   ( x  molar mass) ( m mass given)

Now putting the values in Ideal Gas Law equation

PV = m ÷ x RT

3.29 × 4.60 = 37.96/x × 0.08206 × 375

15.134 = 1168.1241  ÷ x

15.134x = 1168.1241

x = 1168.1241 ÷ 15.13

x = 77.20 gm/mol

If all the units in the formula are put will get cancel only grams/mole will be there. Molecular weight is given by gm/mole.

8 0
3 years ago
What about this one y'alllll
densk [106]

Answer:

um.. is this a quiz or what girl...

6 0
3 years ago
Suppose a student started with 142.0 mg of trans-cinnamic acid, 412 mg of pyridinium tribromide, and 2.30 mL of glacial acetic a
nirvana33 [79]

Answer: Theoretical Yield = 0.2952 g

               Percentage Yield = 75.3%

Explanation:

Calculation of limiting reactant:

n-trans-cinnamic acid moles = (142mg/1000) / 148.16 = 9.584*10⁻⁴ mol

pyridium tribromide moles = (412mg/1000) / 319.82= 1.288*10⁻³ mol

  • n-trans-cinnamic acid is the limiting reactant

The molar ratio according to the equation mentioned is equals to 1:1

The brominated product moles is also = 9.584*10⁻⁴ mol

Theoretical yield = (9.584*10⁻⁴ mol) * (Mr of brominated product)

                             =  (9.584*10⁻⁴ mol) * (307.97) = 0.2952 g

Percentage Yield is : Actual Yield / Theoretical Yield = 0.2223/0.2952

                                                                                           = 75.3%

4 0
4 years ago
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