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liraira [26]
3 years ago
6

Sketch the titration curve for the titration of a generic weak base B with a strong acid. The titration reaction is

Chemistry
1 answer:
Klio2033 [76]3 years ago
7 0

Answer:

Kindly check the attached picture.

Explanation:

Titration is one of the useful concept or practical in chemistry which is used in the determination of the concentration of a particular chemical specie. Without mincing words, let us dive straight into the solution to the question;

(a) Determining the equivalence point using the graph.

=> The equivalence point is the point at which there has been been "enough" addition of the acid to the base to give us the congugate acid. In the diagram showing the curve, it is the point labelled (a).

(b)The next thing is to determine the region with maximum buffering.

=> The position with the maximum buffering ranges from the point labelled (b) in the graph and it is the point when the acid and the base has been added. But the point with the maximum buffering is labeled as point (c).

(c). Determination of the point where pH = pKb.

=> The Point in which the pH = pKb is the point a

(d). The region where pH depends only on [B].

=> The starting point in the point in which the pH is dependent on the concentration of the base, [B].

(e). The region where pH depends only on [BH+].

=> This is the same point with point labelled as (a). Thus, point (a) and (e) are the same.

(f). The region where pH depends only on the amount of excess strong acid is the point labelled as (f) which is known as the post equivalence point.

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2 years ago
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How many grams of Ar are there in 2.25 moles of Ar?
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89.88 g

Explanation:

Atomic Mass of Ar: 39.948

Mass = moles * AM

Replacing moles = 2.25 and AM = 39.948 you get the mass of Ar:

Mass = 2.25 * 39.948

Mass = 89.88 g

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A sample of diborane gas (B2H6), a substance that bursts into flame when exposed to air, has a pressure of 345 torr at a tempera
Hitman42 [59]

Answer:

The final volume is 3.07L

Explanation:

The general gas law will be used:

P1V1 /T1 = P2V2 /T2

V2 =P1 V1 T2 / P2 T1

Give the variables to the standard unit:

P1 = 345 torr = 345 /760 atm = 0.4539atm

T1 = -15°C = -15 + 273 = 258K

V1 = 3.48L

T2 = 36°C = 36+ 273 = 309K

P2 = 468 torr = 468 * 1/ 760 atm = 0.6158atm

V2 = ?

Equate the values into the gas equation, you have:

V2 = 0.4539 * 3.48 * 309 / 0.6158 * 258

V2 = 488.0877 /158.8764

V2 = 3.07

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