I got told if i got a lighter lit it and put it on my self that i should eat a cookie an watch :D should i do it :3

Chemistry

1 answer:

Gnoma [55]2 years ago

4 0

Wait wait what?- don’t put the lighter on yourself-

You might be interested in

Which of the following acids is in household vinegar? A nitric acid hydrochloric acid C fluoric acid D acetic acid

Free_Kalibri [48]

Answer: Out of the given options acetic acid is in household vinegar.

Explanation:

Household vinegar is the one that is commonly used in our home while cooking a number of dishes.

The common name of vinegar is acetic acid and its chemical formula is $CH_{3}COOH$ .

For example, vinegar (acetic acid) is used while making noodles.

Thus, we can conclude that out of the given options acetic acid is in household vinegar.

7 0

3 years ago

The average bond energy (enthalpy) for a C=C double bond is 614 kJ/mol and that of a C−C single bond is 348 kJ/mol. Estimate the

AysviL [449]

Answer:

4.42x10⁻¹⁹ J/molecule

Explanation:

At a double bond, there's sigma and a pi bond, and at a single bond, there's only a sigma bond. Thus, if the energy to break both sigma and pi is 614 kJ/mol, and the energy to break only the sigma bond is 348 kJ/mol, the energy to break only the pi bond is:

E = 614 - 348 = 266 kJ/mol

Knowing that 1 kJ = 1000 J, E = 266,000 J/mol

By Avogadro's number, 1 mol = 6.02x10²³ molecules, thus:

E = 266,000 J/mol * 1mol/6.02x10²³ molecules

E = 4.42x10⁻¹⁹ J/molecule

7 0

3 years ago

Why do scientist use models to study atoms and molecules?

Nesterboy [21]

This allows us to visually see the structure of the atoms/ molecules so we can get a better understanding of what they look like.

6 0

3 years ago

How can I calculate the mass percent of carbon, nitrogen and oxygen in caffeine, C8H10N4O2.

Ahat [919]

You must first calculate the total weight of 1 mole of the substance. You do this by finding the molar weights on the periodic table of each of the elements in the compound:

$8(12.01g)+10(1.008g)+4(14.007g)+2(15.999g)=96.08g+10.08g+56.028g+31.998g=194.186g$