Answer:
The<em> p</em>-value of the test is 0.1212.
Step-by-step explanation:
A one sample <em>z</em>-test can be performed to determine whether the mean hourly wage differs from the reported mean of $24.57 for the goods-producing industries.
The hypothesis is defined as:
<em>H₀</em>: The mean hourly wage is same as the reported mean of $24.57 for the goods-producing industries, i.e. <em>μ</em> = $24.57.
<em>Hₐ</em>: The mean hourly wage differs from the reported mean of $24.57 for the goods-producing industries, i.e. <em>μ</em> ≠ $24.57.
The information provided is:

Compute the test statistic as follows:

The test statistic value is, <em>z</em> = -1.55.
Compute the <em>p</em>-value of the test as follows:

*Use a <em>z</em>-table for the probability.
Thus, the<em> p</em>-value of the test is 0.1212.
Answer: The standard error for sample is 0.0686 .
Step-by-step explanation:
We know that the formula to find the standard error is given by :-

, where s = standard deviation
n= Sample size
As per given , we have
s= $0.4 and n= 34
Then , the standard error for sample is given by :-

Hence , the standard error for sample is 0.0686 .
C is the best choice in my opinion
Answer:
$32 is the sales price.
Step-by-step explanation:
First, change the percentage to a decimal.
60% = 60/100 = 0.6
Next, multiply 0.6 with the regular price ($80)
80 x 0.6 = 48
$48 is the discount. Subtract from the original price
80 - 48 = 32
$32 is the sales price.
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