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icang [17]
3 years ago
9

Suppose you have a rock that, when it solidifies, contains 1 microgram of a radioactive isotope. How much of this isotope remain

s after five half-lives? a) none b) 1/8 microgram c) 1/16 microgram d) 1/32 microgram e) Cannot be determined without knowing the daughter isotope.
Physics
1 answer:
algol133 years ago
7 0

Answer:

d) 1/32 microgram

Explanation:

First half life is the time at which the concentration of the reactant reduced to half.

Second half reaction is the time at which the remaining concentration reduced to half or the initial concentration reduced to 1/4.

Third half life is the time at which the remaining concentration reduced to half or the initial concentration reduced to 1/8.

Forth half life is the time at which the remaining concentration reduced to half or the initial concentration reduced to 1/16.

Fifth half life is the time at which the remaining concentration reduced to half or the initial concentration reduced to 1/32.

The initial mass of the sample = 1 microgram

After 5 half-lives, the mass should reduce to 1/32 of the original.

So the concentration left = 1/32 of 1 microgram = 1/32 microgram

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A 89.3 kg horizontal circular platform rotates freely with no friction about its center at an initial angular velocity of 1.77 r
balu736 [363]

Answer:

\omega_{2} = 1.107\,\frac{rad}{s}

Explanation:

Let assume that circular platform is a solid cylinder. Given the absence of external forces, the situation can be analyzed by applying the Principle of Angular Momentum, which states that:

I_{1}\cdot \omega_{1} = I_{2}\cdot \omega_{2}

The initial moment of inertia is:

I_{1} = \frac{1}{2}\cdot (89.3\,kg)\cdot (1.69\,m)^{2}

I_{1} = 127.525\,kg\cdot m^{2}

Likewise, the final moment of inertia is:

I_{2} = 127.525\,kg\cdot m^{2} + (8.83\,kg)\cdot (1.352\,m)^{2} + (21.1\,kg)\cdot (1.69\,m)^{2}

I_{2} = 203.929\,kg\cdot m^{2}

The final angular speed is:

\omega_{2} = \frac{I_{1}}{I_{2}} \cdot \omega_{1}

\omega_{2} = \frac{127.525\,kg\cdot m^{2}}{203.929\,kg\cdot m^{2}} \cdot (1.77\,\frac{rad}{s} )

\omega_{2} = 1.107\,\frac{rad}{s}

4 0
3 years ago
Read 2 more answers
Vibrations that move through the ground carrying the energy released during an earthquake are called
Alekssandra [29.7K]
Answer is Seismic Wave
4 0
3 years ago
¿Cuál de las siguientes no es un tipo de fuerza de roce
Degger [83]
Enertia es el answer de tu question
8 0
3 years ago
A police car is driving down the street with it's siren on. You are standing still on the sidewalk beside the street. If the fre
diamong [38]

Answer:

A) 1568.60 Hz

Explanation:

This change is frequency happens due to doppler effect

The Doppler effect is the change in frequency of a wave in relation to an observer who is moving relative to the wave source

f_(observed)=\frac{(c+-V_r)}{(C+-V_s)} *f_(emmited)\\

where

C = the propagation speed of waves in the medium;

Vr= is the speed of the receiver relative to the medium,(added to C, if the receiver is moving towards the source, subtracted if the receiver is moving away from the source;

Vs= the speed of the source relative to the medium, added to C, if the source is moving away from the receiver, subtracted if the source is moving towards the receiver.

A) Here the Source is moving towards the receiver(C-Vs)

and the receiver is standing still (Vr=0) therefore the observed frequency should get higher

f_(observed)=\frac{C}{C-V_s} *f_(emmited)\\=\frac{343}{343-15}*1500\\ =1568.60 Hz

6 0
3 years ago
The demand for your hand-made skateboards, in weekly sales, is q = −3p + 700 if the selling price is $p. You are prepared to sup
Y_Kistochka [10]

Answer:

you should sell your skateboards at $240

Explanation:

The price p to sell your skateboards for so that there is neither a shortage nor a surplus is the price that makes equal the quantity of sales and the quantity of supply, so p is equal to:

q (sales) = q (supply)

-3p + 700 = 2p - 500

700 + 500 = 2p + 3p

1200 = 5p

1200/5 = p

$240 = p

3 0
3 years ago
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